Look back at the matrix A. Can you spot a dependency amongst its rows? While it is possible to find matrices where there is a dependency among the rows (or columns), such matrices are rather rare. If you create a random matrix, it's rather likely that it will have no such dependencies -- and will therefore be invertible. There are multiple ways to create random matrices in sage. Try executing the following cell to get a random 4 x 4 matrix, then find it's inverse using the augmentation/row reduction process. How can you spot whether you got unlucky and ran into a non-invertible matrix? A = random_matrix (ZZ,4,4); A 1 15 -9 0 0 -1 -27 [ 3 [ 0 [ 0 [-7 1 -2] 1] 0] 0]

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Using SageMath: 

A =
Look back at the matrix A. Can you spot a dependency amongst its rows?
While it is possible to find matrices where there is a dependency among the rows (or columns), such matrices are rather rare. If you create a
random matrix, it's rather likely that it will have no such dependencies -- and will therefore be invertible.
There are multiple ways to create random matrices in sage.
Try executing the following cell to get a random 4 x 4 matrix, then find it's inverse using the augmentation/row reduction process.
How can you spot whether you got unlucky and ran into a non-invertible matrix?
random_matrix (ZZ,4,4); A
1
1
15 -9
0
0
-1 -27
[
3
[
0
[
0
[ -7
-2]
1]
0]
0]
Transcribed Image Text:A = Look back at the matrix A. Can you spot a dependency amongst its rows? While it is possible to find matrices where there is a dependency among the rows (or columns), such matrices are rather rare. If you create a random matrix, it's rather likely that it will have no such dependencies -- and will therefore be invertible. There are multiple ways to create random matrices in sage. Try executing the following cell to get a random 4 x 4 matrix, then find it's inverse using the augmentation/row reduction process. How can you spot whether you got unlucky and ran into a non-invertible matrix? random_matrix (ZZ,4,4); A 1 1 15 -9 0 0 -1 -27 [ 3 [ 0 [ 0 [ -7 -2] 1] 0] 0]
Expert Solution
Step 1: Given

The given matrix is A equals open square brackets table row 3 1 1 cell negative 2 end cell row 0 15 cell negative 9 end cell 1 row 0 0 0 0 row cell negative 7 end cell cell negative 1 end cell cell negative 27 end cell 0 end table close square brackets.

To find any form of dependency amongst its rows.

To find whether the matrix is invertible.

If invertible to find the inverse using the augmenttion or row reduction process.


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