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log₂x + log₂ (2x² + 5x − 14) = log5 125

log₂x + log₂ (2x² + 5x − 14) = log5 125

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the problem using the text. Make sure restrictions are stated.
Solve the given equation for x. Make sure to state any restrictions and ignore any extraneous/inadmissible solutions. Express final answers in exact form (no decimals). In the interest of saving time when you are determining your restrictions, the solutions to 2x² + 5x - 14 = 0 are 1.7 and -4.2. (You do not need to show this, but these numbers will b needed as you state your restrictions) • • Hint 1: Take note that the base of the logarithms on the left and right side are differen Hint 2: This will require polynomial division. If you cannot find a factor that will divi into your polynomial (within the possibilities of +1,2,3,4), then state you can't find a factor, and in the line below, change the constant to whatever number you need to cha it to so that it will factor (positive or negative) by one of those numbers and just facto log₂ x + log₂ (2x² + 5x −14) = log5 125
Transcribed Image Text:Solve the given equation for x. Make sure to state any restrictions and ignore any extraneous/inadmissible solutions. Express final answers in exact form (no decimals). In the interest of saving time when you are determining your restrictions, the solutions to 2x² + 5x - 14 = 0 are 1.7 and -4.2. (You do not need to show this, but these numbers will b needed as you state your restrictions) • • Hint 1: Take note that the base of the logarithms on the left and right side are differen Hint 2: This will require polynomial division. If you cannot find a factor that will divi into your polynomial (within the possibilities of +1,2,3,4), then state you can't find a factor, and in the line below, change the constant to whatever number you need to cha it to so that it will factor (positive or negative) by one of those numbers and just facto log₂ x + log₂ (2x² + 5x −14) = log5 125
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