load resistor operating at an average power of 5W. Finalize answers as: RL(standard)= Isavertgmin=_ Design the given circuit shown and determine the standard value of the : Idavertgmin=: Idpkrtgmin=; Vdpkrtgmin= D1 DA 5:1 120 V rms D2 RL V out elll
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- aloulated m O1 the value you Up = A cos wt +1o Calaulate maarli)-min(i) =? Use constant voltage drop mad. Don7 to write units. . - 3.7V forgetA circuit consists of an AC voltage source, a 10-ohm resistor, and a capacitor, all connected in series. The magnitude of the impedance of the capacitor is also 10 ohms. Which of the following is true about the source voltage and the current through the circuit? a. Insufficient information is given. b. The source voltage will lag the current. c. The source voltage will lead the current. d. The source voltage will be in-phase with the current.Combination circuit what is PT? RT? IT? Voltage Across each load?
- What will happen to the value of the impedance if the resistance will be increased or decreased? Explain...a) Graphically show the differences between alternating current voltage (A.C) and direct current voltage (D.C). What are the advantages of A.C compared to D.C?Q1. a) An SCR based AC power controller circuit is given in Figure 1. The circuit connects a 240V 50Hz AC source vi to a resistive load with resistance of 100. If the delay angle is a-15°, draw the waveforms of the load voltage Vo, and the voltage across SCR2. Calculate the power supplied to the load. + Vi Va + 2 SCR2 H₁₁ SCR₁ Figure 1 SCR based AC power control circuit Va + 2 io b) Figure 2 is a single phase 2-level voltage source converter (VSC) with a DC voltage Vd-200V. A PWM scheme, by comparing a reference value with a 10kHz triangle waveform, is used to control the switches S₁ and S2. The modulation index of the PWM is m=0.8. With the aid of graphs explain how pulse signals for the switches are generated, sketch the output voltage Vo, determine the duty cycle, and calculate the average output voltage. + Vo + Vo √ ₂ == Figure 2 A single phase VSC
- 5. For the circuit shown in Figure C3 а. Draw the DC loạd line in the Graph C3 Ic VCE R1 5kQ No Signal V BB Vcc 12 V Figure C3 Graph C3Given the center-tap fullwave rectifier circuit shown 220V 60Hz (+2) 220V:Es1-0-Es2 Es1 E$2 D1 D2 RL The transformer is rated 220V:12V-0-12V (Es1=Es2=12V) and the average current through the load RL is 400mA. Determine: (a) Average value, RMS value, and frequency of load voltage VRL. (b) Power dissipated by the load RL. (c) Average current and PIV of each diode.what is ripple ? how to minimize the rippl , draw the circuit and show ??
- for The Gircuit shown in figure if (B =50) tind The values of CIe). and of Then express The change in value by apercentage + 15U RB, = 100Ka R82 = 50 KQ RE 3K2 %3DWhat is the load current for the circuit shown in the figure? Please choose one: a. 9.0 mA b. 7.5 mA c. 3.0 mA D. 6.0 mAAn AC circuit is shown in the diagram. The source of emf has a peak voltage of 9.00 V and a frequency of 60.0 Hz. Assume the wires contribute a negligible amount to the resistance and the AC source has negligible internal resistance. 524 2 493 2 1.56 k2 a) Find the equivalent resistance of the circuit. Redraw the circuit showing the equivalent resistor and use this simplified circuit for the rest of the problem. 315 2 Re = b) Find the rms current. 9.00 V, 60.0 Hz c) If the current is zero at time t= 0, find the first two times (after time t-0) that the current is equal to its rms value. and d) Find the average power dissipated by the circuit.