ll Sprint n 30% 3:33 PM Done bartleby.com = bartleby Q&A Engineering / Mechan. .. /Q&A Lib. .. is knawn that the Connethna red AB eut M F.d M FxF M -F sin 6 11 C0.042mi+0.056 mj 1 and for Force we can write F = -Fi F = -2500 N Since, force is given only in negative x-axis So, we take only x- component Step 2
ll Sprint n 30% 3:33 PM Done bartleby.com = bartleby Q&A Engineering / Mechan. .. /Q&A Lib. .. is knawn that the Connethna red AB eut M F.d M FxF M -F sin 6 11 C0.042mi+0.056 mj 1 and for Force we can write F = -Fi F = -2500 N Since, force is given only in negative x-axis So, we take only x- component Step 2
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter1: Introduction To Statics
Section: Chapter Questions
Problem 1.12P: A differential equation encountered in the vibration of beams is d4ydx4=2D where x = distance...
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I received an answer for my last question and I am still a bit confused. In the solution you said that F only has a horizontal component, how did you arrive at that? The question says that F is down and to the left.
![ll Sprint
n 30%
3:33 PM
Done
bartleby.com
= bartleby
Q&A
Engineering / Mechan. .. /Q&A Lib. ..
is knawn that the Connethna red AB eut
M F.d
M FxF
M -F
sin 6
11
C0.042mi+0.056 mj
1
and for Force we can write
F = -Fi
F = -2500 N
Since, force is given only in negative x-axis
So, we take only x- component
Step 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fed8f022e-9924-48a3-b7ba-3e571c1956df%2Fd19323f2-8cd7-48f1-892e-b425377f9f9c%2F2v1end.png&w=3840&q=75)
Transcribed Image Text:ll Sprint
n 30%
3:33 PM
Done
bartleby.com
= bartleby
Q&A
Engineering / Mechan. .. /Q&A Lib. ..
is knawn that the Connethna red AB eut
M F.d
M FxF
M -F
sin 6
11
C0.042mi+0.056 mj
1
and for Force we can write
F = -Fi
F = -2500 N
Since, force is given only in negative x-axis
So, we take only x- component
Step 2
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