Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple randomsamples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater thanthe mean amount from city #2 residents.Click the icon to view the data table of strontium-90 amounts.What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2.O B. Ho: H1 = H2A. Ho: H1 = H2H: H1 # H2H: H1> H2O D. Ho: H1 SH2H: H > H2OC. Ho: H1 #42H: 1>H2The test statistic is. (Round to two decimal places as needed.) o view the data table of strontium-90 amounts.d alternative hypotheses? Assume that population 1 consists of amourcity #2.More infoCity #1101City #21178666121100(Round to two decimal places as needed.)1168510180107104213110110111140133290100310101145209PrintDone

The random variable amount of strontium follows normal distribution. There are two independent samples which are city#1 and city #2. We have to test whether the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents or not. This is two-independent sample t-test with right-tailed.EXCEL (Data Analysis) Procedure: Step 1: In EXCEL sheet, enter City #1 in one column and enter City #2 in one column. Step 2: In Data, select Data Analysis and choose t test: Two-Sample Assuming Unequal Variances. Step 3: In Input Variable 1 Range: select City #1. Step 4: In Input Variable 2 Range: select City #2. Step 5: Select Lables. Click Ok. EXCEL (Data Analysis) output: The test statistic is 1.47.P-value = 0.080. Conclusion: Since p-value (=0.080) > 0.01, then do not reject the null hypothesis. There is insufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents.