please help solve below questions pertaining to attached imagefind the test statisiticfind the p valueState the conclusion for the test. A. Reject the null hypothesis. There is sufficient evidence to support the claim that archbishops have lower mean longevity than monarchs. B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that archbishops have lower mean longevity than monarchs. C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that archbishops have lower mean longevity than monarchs.D. Reject the null hypothesis. There is not sufficient evidence to support the claim that archbishops have lower mean longevity than monarchs. Listed below are the numbers of years that archbishops and monarchs in a certain country lived after their election or coronation. Assume that the two samples are independent simple random samples selected from normally distributecpopulations. Do not assume that the population standard deviations are equal. Use a .05 significance level to test the claim that the mean longevity for archbishops is less than the mean for monarchs after coronation. All measurementyears.Click the icon to view the table of longevities of archbishops and monarchs.What are the null and alternative hypotheses? Assume that population 1 consists of the longevity of archbishops and population 2 consists of the longevity of monarchs.A. Ho: H1 # H2H1: H1> H2B. Ho: H1 = H2H1: H1 # H2C. Ho: H1 = H2H1: H1 H2The test statistic is(Round to two decimal places as needed.) Longevities of Archbishops and Monarchs18Archbishops15161518315191013109.1611111217189.9.1714Monarchs181713131719161815201918PrintDoneO 500

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Description: please help solve below questions pertaining to attached imagefind the test statisiticfind the p valueState the conclusion for the test. A. Reject the null hypothesis. There is sufficient evidence to support the claim that archbishops have lower mean

Answered: Listed below are the numbers of years…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

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please help solve below questions pertaining to attached image

find the test statisitic

find the p value

State the conclusion for the test.

A. Reject the null hypothesis. There is sufficient evidence to support the claim that archbishops have lower mean longevity than monarchs.

B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that archbishops have lower mean longevity than monarchs.

C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that archbishops have lower mean longevity than monarchs.

D. Reject the null hypothesis. There is not sufficient evidence to support the claim that archbishops have lower mean longevity than monarchs.

Listed below are the numbers of years that archbishops and monarchs in a certain country lived after their election or coronation. Assume that the two samples are independent simple random samples selected from normally distributec
populations. Do not assume that the population standard deviations are equal. Use a .05 significance level to test the claim that the mean longevity for archbishops is less than the mean for monarchs after coronation. All measurement
years.
Click the icon to view the table of longevities of archbishops and monarchs.
What are the null and alternative hypotheses? Assume that population 1 consists of the longevity of archbishops and population 2 consists of the longevity of monarchs.
A. Ho: H1 # H2
H1: H1> H2
B. Ho: H1 = H2
H1: H1 # H2
C. Ho: H1 = H2
H1: H1 <H2
D. Ho: H1 SH2
H1: 41 > H2
The test statistic is
(Round to two decimal places as needed.)

Longevities of Archbishops and Monarchs
18
Archbishops
15
16
15
18
3
15
19
10
13
10
9.
16
11
11
12
17
18
9.
9.
17
14
Monarchs
18
17
13
13
17
19
16
18
15
20
19
18
Print
Done
O 500

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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