Listed below are the lead concentrations in ug/g measured in different traditional medicines. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicinesis less than 16 µg/g. Assume that the sample is a simple random sample.1016.521.51913 16.5419 173 DAssuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses?Ο Α. H μ= 16 μg gΗ : μ< 16 μαgO B. Ho: u> 16 ug/gH,: µ< 16 ug/gO D. Ho: H= 16 µg/gO C. Ho:μ= 16 μggH1: p> 16 µg/gH;: u# 16 ug/gDetermine the test statistic.(Round to two decimal places as needed.)Determine the P-value.|(Round to three decimal places as needed.)State the final conclusion that addresses the original claim.Ho. There isV 16 µg/g.evidence to conclude that the mean lead concentration for all such medicines is

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MATLAB: An Introduction with Applications

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ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

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Listed below are the lead concentrations in ug/g measured in different traditional medicines. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines
is less than 16 µg/g. Assume that the sample is a simple random sample.
10
16.5
21.5
19
13 16.5
4
19 17
3 D
Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses?
Ο Α. H μ= 16 μg g
Η : μ< 16 μαg
O B. Ho: u> 16 ug/g
H,: µ< 16 ug/g
O D. Ho: H= 16 µg/g
O C. Ho:μ= 16 μgg
H1: p> 16 µg/g
H;: u# 16 ug/g
Determine the test statistic.
(Round to two decimal places as needed.)
Determine the P-value.
|(Round to three decimal places as needed.)
State the final conclusion that addresses the original claim.
Ho. There is
V 16 µg/g.
evidence to conclude that the mean lead concentration for all such medicines is

Expert Solution

Step 1

Given claim: The mean lead concentration for all such medicines is less than 16.

Null Hypothesis:

$H_{0} : μ = 16 μ g / g$

Alternative Hypothesis:

$H_{1} : μ < 16 μ g / g$

Correct option:

Step 2

Test statistic:

Given information:

$\bar{x} = 13.95, f r o m t h e e x c e l f u n c t i o n, = A V E R A G E (K 9 : K 18) s = 6.3746, f r o m t h e e x c e l f u n c t i o n, = S T D E V . S (K 9 : K 18) n = 10$

$t = \frac{\bar{x} - μ}{\frac{s}{\sqrt{n}}} = \frac{13.95 - 16}{\frac{6.3746}{\sqrt{10}}} = - 1.02$

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