Use a significance level ofa=0.05 to test the claim that u = 19.6. The sample data consists of 10 scores for which x =20.1 and s=4.1. state the null and alternative hypotheses, compute the value of the test statistic, and find the P-value for the sample. Sstate your conclusions about the claim. H :H= 19.6 H, : µz19.6 OTest statistic: t=0.3856. P-Value: P=0.7087. Reject H, :H = 19.6. Since P>a, there is sufficient evidence to support the claim that the mean is different from 19.6. H: H= 20.1 H : µz 20.1 O Test statistic: t=20.1. P-Value: P= 0.7087. Accept Ho H = 20.1. Since P>a, there is not sufficient evidence to support the claim that the mean is different from 20.1. H:u= 19.6 Huz19.6

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**Hypothesis Testing: Determining the Statistical Significance**

**Problem Statement:**
Use a significance level of \( \alpha = 0.05 \) to test the claim that \( \mu = 19.6 \). The sample data consists of 10 scores for which \( \bar{x} = 20.1 \) and \( s = 4.1 \). State the null and alternative hypotheses, compute the value of the test statistic, and find the P-value for the sample. State your conclusions about the claim.

**Step-by-Step Solution:**

1. **State the Null and Alternative Hypotheses:**
   - \( H_0: \mu = 19.6 \)
   - \( H_1: \mu \neq 19.6 \)

2. **Compute the Test Statistic and P-Value:**
   - Test Statistic: \( t = 0.3856 \)
   - P-Value: \( P = 0.7087 \)

   Since \( P > \alpha \), there is sufficient evidence to support the claim that the mean is different from 19.6.

   Conclusion: Reject \( H_0: \mu = 19.6 \).

3. **Second Set of Hypotheses:**
   - \( H_0: \mu = 20.1 \)
   - \( H_1: \mu \neq 20.1 \)

4. **Compute the Test Statistic and P-Value:**
   - Test Statistic: \( t = 20.1 \)
   - P-Value: \( P = 0.7087 \)

   Since \( P > \alpha \), there is not sufficient evidence to support the claim that the mean is different from 20.1.

   Conclusion: Accept \( H_0: \mu = 20.1 \).

5. **Third Set of Hypotheses:**
   - \( H_0: \mu = 19.6 \)
   - \( H_1: \mu \neq 19.6 \)

**Graphical Representation:**
Unfortunately, the image provided does not contain a graphical representation. If there were graphs or diagrams, they would typically show:
   - A t-distribution curve to illustrate the position of the test statistic and shaded area representing the P-value.
   - A visual comparison between the sample mean and the hypothesized population mean.
Transcribed Image Text:**Hypothesis Testing: Determining the Statistical Significance** **Problem Statement:** Use a significance level of \( \alpha = 0.05 \) to test the claim that \( \mu = 19.6 \). The sample data consists of 10 scores for which \( \bar{x} = 20.1 \) and \( s = 4.1 \). State the null and alternative hypotheses, compute the value of the test statistic, and find the P-value for the sample. State your conclusions about the claim. **Step-by-Step Solution:** 1. **State the Null and Alternative Hypotheses:** - \( H_0: \mu = 19.6 \) - \( H_1: \mu \neq 19.6 \) 2. **Compute the Test Statistic and P-Value:** - Test Statistic: \( t = 0.3856 \) - P-Value: \( P = 0.7087 \) Since \( P > \alpha \), there is sufficient evidence to support the claim that the mean is different from 19.6. Conclusion: Reject \( H_0: \mu = 19.6 \). 3. **Second Set of Hypotheses:** - \( H_0: \mu = 20.1 \) - \( H_1: \mu \neq 20.1 \) 4. **Compute the Test Statistic and P-Value:** - Test Statistic: \( t = 20.1 \) - P-Value: \( P = 0.7087 \) Since \( P > \alpha \), there is not sufficient evidence to support the claim that the mean is different from 20.1. Conclusion: Accept \( H_0: \mu = 20.1 \). 5. **Third Set of Hypotheses:** - \( H_0: \mu = 19.6 \) - \( H_1: \mu \neq 19.6 \) **Graphical Representation:** Unfortunately, the image provided does not contain a graphical representation. If there were graphs or diagrams, they would typically show: - A t-distribution curve to illustrate the position of the test statistic and shaded area representing the P-value. - A visual comparison between the sample mean and the hypothesized population mean.
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