Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of thesame woman. Assume that the paired sample data is a simple random sample and that the differenceshave a distribution that is approximately normal. Use a 0.05 significance level to test for a differencebetween the measurements from the two arms. What can be concluded?Right armLeft arm147146133130133173172186146149In this example, P. is the mean value of the differences d for the population of all pairs of data, whereeach individual difference d is defined as the measurement from the right arm minus the measurementfrom the left arm. What are the null and alternative hypotheses for the hypothesis test?O A. Hp Ha 7 0H1: Pd = 0O B. H, Ha = 0H1 Ha 7 OO D. Ho Ha 0O C. H, Ha + 0H1 Ha> 0Identify the test statistic. Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of thesame woman. Assume that the paired sample data is a simple random sample and that the differenceshave a distribution that is approximately normal. Use a 0.05 significance level to test for a differencebetween the measurements from the two arms. What can be concluded?146Right armLeft arm147133130133ロ173172186146149Identify the test statistic.%3D(Round to two decimal places as needed.)Identify the P-value.P-value = (Round to three decimal places as needed.)What is the conclusion based on the hypothesis test?Since the P-value isthan the significance level,the null hypothesis. Theresufficient evidence to support the claim of a difference in measurements between the twoarms.Click to select your answer(s).(2,

Name: Listed below are systolic blood pressure measurements (mm Hg) taken f
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Description: Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of thesame woman. Assume that the paired sample data is a simple random sample and that the differenceshave a distribution that is approximately normal.

From the provided information, The difference table can be obtained as: di = right arm – left arm -26 -26 -53 -16 -16 Sample size (n) = 5The mean and standard deviation of difference can be obtained as:The hypotheses are as follow: H0: µd = 0 H1: µd ≠ 0 Level of significance (α) = 0.05 Since, the population standard deviation is unknown, therefore, the t distribution will be used. The value of the test statistic can be obtained as:The degree of freedom = n – 1 = 5 – 1 = 4 The p value of the test statistic at 4 degrees of freedom from the t value table is 0.016. Since, the p value is less than the significance level, therefore, we reject the null hypothesis. There is sufficient evidence to support the claim of a difference in measurement between the two arms.

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Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm Left arm 147 146 133 130 133 173 172 186 146 149 Identity the test statistic. t= |(Round to two decimal places as needed.) Identify the P-value. P-value =(Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is than the significance level, the null hypothesis. There sufficient evidence to support the claim of a difference in measurements between the two arms.

Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm Left arm 147 146 133 130 133 173 172 186 146 149 Identity the test statistic. t= |(Round to two decimal places as needed.) Identify the P-value. P-value =(Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is than the significance level, the null hypothesis. There sufficient evidence to support the claim of a difference in measurements between the two arms.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Do men score higher on average compared to women on their statistics finals? Final exam scores of twelve randomly selected male statistics students and twelve randomly selected female statistics students are shown below. Male: 89 58 94 91 67 69 Female: 70 75 47 49 86 61 76 48 79 77 50 70 Assume both follow a Normal distribution. What can be concluded at the the a = 0.01 level of significance level of significance? For this study, we should use Select an answer 86 76 95 91 71 72 a. The null and alternative hypotheses would be: Ho: Select an answer H₁: Select an answer Select an answer Select an answer. Select an answer Select an answer (please enter a decimal) (Please enter a decimal) (please show your answer to 3 decimal places.) b. The test statistic c. The p-value = d. The p-value is ? a e. Based on this, we should Select an answer the null hypothesis. f. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) O The results are statistically…
Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm 148 145 138 130 136 Left arm 166 179 176 144 141 In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test? A. H0: μd≠0 H1: μd=0 B. H0: μd=0 H1: μd≠0 C. H0: μd≠0 H1: μd>0 D. H0: μd=0 H1: μd<0 Identify the test statistic. t= (Round to two decimal places as needed.)…
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Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm 142 132 127 137 130 D Left arm 174 172 184 137 147 O A. Ho: Hd =0 B. Ho: Ha 0 H1: Hd =0 %3D OC. Ho: Hd = 0 H1: Hd 0 Identify the test statistic. (Round to two decimal places as needed.) t= Identify the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test?
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