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Liquid water flows isothermally at 20°C through a one-inlet, one-exit duct operating at steady state. The duct's inlet and exit diameters are 0.02 m and 0.04 m, respectively. At the inlet, the velocity is 50 m/s and the pressure is 1 bar. At the exit, V, T A1 = 0.2 m2 P1=5 bar rate in kals and

Liquid water flows isothermally at 20°C through a one-inlet, one-exit duct operating at steady state. The duct's inlet and exit diameters are 0.02 m and 0.04 m, respectively. At the inlet, the velocity is 50 m/s and the pressure is 1 bar. At the exit, V, T A1 = 0.2 m2 P1=5 bar rate in kals and

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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**Text:** Liquid water flows isothermally at 20°C through a one-inlet, one-exit duct operating at steady state. The duct’s inlet and exit diameters are 0.02 m and 0.04 m, respectively. At the inlet, the velocity is 50 m/s and the pressure is 1 bar. At the exit, determine the mass flow rate, in kg/s, and velocity, in m/s. **Diagram Explanation:** The diagram illustrates a duct with a water vapor flow: - **Inlet (1):** - Velocity (V₁) - Temperature (T₁) - Area (A₁ = 0.2 m²) - Pressure (p₁ = 5 bar) - **Exits (2 and 3):** - Both exits have the same conditions: - Pressure (p₂ = p₃ = 4.8 bar) - Temperature (T₂ = T₃ = 320°C) - The product of area and velocity is equal for both exits: (AV)₂ = (AV)₃ This setup is used to find the mass flow rate and velocity at the exit of the duct.
Transcribed Image Text:**Text:** Liquid water flows isothermally at 20°C through a one-inlet, one-exit duct operating at steady state. The duct’s inlet and exit diameters are 0.02 m and 0.04 m, respectively. At the inlet, the velocity is 50 m/s and the pressure is 1 bar. At the exit, determine the mass flow rate, in kg/s, and velocity, in m/s. **Diagram Explanation:** The diagram illustrates a duct with a water vapor flow: - **Inlet (1):** - Velocity (V₁) - Temperature (T₁) - Area (A₁ = 0.2 m²) - Pressure (p₁ = 5 bar) - **Exits (2 and 3):** - Both exits have the same conditions: - Pressure (p₂ = p₃ = 4.8 bar) - Temperature (T₂ = T₃ = 320°C) - The product of area and velocity is equal for both exits: (AV)₂ = (AV)₃ This setup is used to find the mass flow rate and velocity at the exit of the duct.
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