Limiting ReagentEXAMPLE Limiting ReagentReaction 1-9 requires one mole of oxalate for each mole of calcinum.Ca + Co - CalC,0.) - H,O(0)(1-9)OulteCaki malateIr you mix 1.00 g of CaCl; (FM 110.98) with 1.15 g of NaC0, (FM 134.00) in water.which is the limiting reagent? What fractiou of the noolimiting reagent is left over?Solution The available moles of each reagent, areLI5 g NaCO. K S manol Co100 g CaCl110.98 g/mol-9.01 mnol Ca134.00 p/molThe reaction requires I mol Ca for I mol C0 . so oxalate will be used up firstThe Ca" remaining is 9.01(0.43 mmol/9.01 mmol) - 4.8%8.58 - 0.43 mmol. The fraction of unreacted Ca" isTEST YOURSELF The reaction SHCO, + 2Mno, + 6H 1OCO, + 2Ma+ KH,0requires 5 mol H,CO, for 2 mol MnO, If you nix L.15 g NaCO, (FM 134.00) with0.60 g KMn0, (FM 158.03) and ekcess aqueous acid, which reactant is limiting? Howmuch CO, is produced?De

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Limiting Reagent EXAMPLE Limiting Reagent Reaction 1-9 requires one mole of oxalate for each mole of calcinm. Ca + Co - CaC,0.) - H,O(0) (1-9) Oulte Cakcien oalate Ir you mix 1.00 g of CaCl; (FM 110.98) with 1.15 g of NaC0, (FM 134.00) in water. which is the limiting teagent? What fractiou of the nolimiting reagent is left over? Solution The available moles of each reagent are L15 g NaCO. K S manol Co 100 g CaCl 110.98 g/mol -9.01 mnol Ca 134.00 g/mol The reaction requires I mol Ca for I mol C0 so oxalate will be used up first The Ca" remaining is 9.01 (0.43 mmol/9.01 mmol)- 4.8% 8.58 - 0.43 mmol. The fraction of unreacted Ca is TEST YOURSELF The reaction SHCO, + 2Mn0, + 6H 1OCO, + 2Ma+ KH,0 requires 5 mol H,CO, for 2 mol MnO, If you nix L.15 g NaCO, (FM 134.00) with 0.60 g KMnO, (FM 158.03) and ekcess aqueous acid, which reactant is limiting? How much CO, is produced? Der

Limiting Reagent EXAMPLE Limiting Reagent Reaction 1-9 requires one mole of oxalate for each mole of calcinm. Ca + Co - CaC,0.) - H,O(0) (1-9) Oulte Cakcien oalate Ir you mix 1.00 g of CaCl; (FM 110.98) with 1.15 g of NaC0, (FM 134.00) in water. which is the limiting teagent? What fractiou of the nolimiting reagent is left over? Solution The available moles of each reagent are L15 g NaCO. K S manol Co 100 g CaCl 110.98 g/mol -9.01 mnol Ca 134.00 g/mol The reaction requires I mol Ca for I mol C0 so oxalate will be used up first The Ca" remaining is 9.01 (0.43 mmol/9.01 mmol)- 4.8% 8.58 - 0.43 mmol. The fraction of unreacted Ca is TEST YOURSELF The reaction SHCO, + 2Mn0, + 6H 1OCO, + 2Ma+ KH,0 requires 5 mol H,CO, for 2 mol MnO, If you nix L.15 g NaCO, (FM 134.00) with 0.60 g KMnO, (FM 158.03) and ekcess aqueous acid, which reactant is limiting? How much CO, is produced? Der

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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