Light with wavelength i passes through a narrow slit of width w and is seen on a screen which is located at a distance D in front of the slit. The first minimum of the diffraction pattern is at distance d from the middle of the central maximum. Calculate the wavelength of light if D=3.1 m, d=1 mm and w = VAD. Give your answer in nanometers. Answer: nm

Light with wavelength i passes through a narrow slit of width w and is seen on a screen which is located at a distance D in front of the slit. The first minimum of the diffraction pattern is at distance d from the middle of the central maximum. Calculate the wavelength of light if D=3.1 m, d=1 mm and w = VAD. Give your answer in nanometers. Answer: nm

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

The figure shows the light intensity on a screen behind a double slit. The slit spacing is 0.220mm and the screen is 2.20m behind the slits. a. What is the width of the central maximum? In mm.
The spacing between two slits is 5.90×10^-3 m in a Young's double slit experiment. The distance from the slits to the screen is 1.00 m, and the distance from the central bright maximum to the third maxima is 2.50x10^-4 m. Determine the wavelength of the incident light used in the experiment. Include a labelled diagram.
A laser beam is normally incident on a single slit with width 0.620 mm. A diffraction pattern forms on a screen a distance 1.35 m beyond the slit. The distance between the positions of zero intensity on both sides of the central maximum is 2.18 mm. Calculate the wavelength of the light (in nm). nm Need Help? Read It
State the conditions necessary for interference to take place. In a Young's 2-slit experiment, the separation of the interference bands w is given by the equation: w=?D/a where λ is the wavelength of the light, D is the distance from the double slit to the screen and a is the distance between the slits. Given that D = 5 m, a= o.25 cm and λ = 618 nm, calculate the fringe width w. Give your answer in millimetres.
A beam of monochromatic light with a wavelength of 500 nm is directed through an absorber having 5 equally narrow slits separated by 20 um between adjacent slits. The resulting diffraction pattern is observed on a screen that is perpendicular to the direction of light and 5 m from the slits. The intensity of the central maximum is 1.3 W/m2. Calculate the distances from the central maximum to the first and second principal maxima respectively. on the screen A. 8 cm and 25 cm B. 8 cm and 12 cm C. 12.5 cm and 25 cm D. 25 cm and 9.2 cm E. 9.2 cm and 23 cm
When illuminating the observation screen directly, without any slits, you notice that the laser has a spread, meaning that the light on the screen becomes larger as you increase the distance between you and the screen. Determine the angular spread of the 710.5 nm wavelength laser beam if the circular aperture of the laser is 0.7 mm in diameter. Enter your answer in milli-rad with 2 decimal place precision
A sheet of paper 0.014 cm thick separates two sheets of glass to form an air wedge 16.5 cm long. When the air wedge is illuminated with monochromatic light, the distance between the centers of the first and eighth dark bands is 2.3 mm. Determine the wavelength of the light, in nm,
If you can read the bottom row of your doctor's eye chart, your eye has a resolving power of one arcminute, equal to 1.67×10−2 degrees. if this resolving power is diffraction-limited, to what effective diameter of your eye's optical system does this correspond? Use Rayleigh's criterion and assume that the wavelength of the light is 540 nmnm . Express your answer in millimeters to three significant figures. in nm
A laser light source with wavelength λ = 545 nm is incident on a diffraction grating (as in the figure). The grating has 495 slits per mm. An observation screen is a distance L = 0.35 m from the grating. What is the separation between individual slits in the grating? Be careful with units: 1 nm = 10-9 m, 1 mm = 10-3 m, and 1 cm = 10-2 m. d = nm What is the distance y along the screen where the first-order diffraction peak is observed? y= cm source grating m=1
In a double-slit interference experiment, d is the distance between the centers of the slits and w is the width of each slit, as shown in the figure above. For incident plane waves, if an interference maximum on a distant screen will fall at a diffractive minimum, which of the following relations between d and w is correct? @ 3d=2w @ 2d=3w. @d=3¹/2w. @d=2¹/2w @ 2d=w.
In a double slit experiment the first minimum for 405 nm violet light is at an angle of 41°. λ = 405 nmθ = 41 ° Find the distance between the two slits in micrometers. d =?
You measure three segments of the distance between a diffraction slit an the screen on which the pattern forms: x1 = (15.8 ± 0.2) cm, x2 = (6.7 ± 0.1) cm, and x3 = (11.3 ± 0.1). What is the uncertainty of the total distance x1 + x2 + x3? Group of answer choices 0.4 cm 0.5 cm 0.2 cm 0.3 cm 0.1 cm