Light of wavelength of 102.6 nm is emitted by a hydrogen atom. What are:a) Principal quantum number of lower (final) orbitb) Principal quantum number of higher (initial) orbit Of transition producing this emission?c) If electron angular quantum number of initial state is s what is orbital quantum number in the final state?Please show the work! 2. Light of wavelength of 102.6 nm is emitted by a hydrogen atom. What are: a) Principal quantum number of lower (final) orbit b) Principal quantum number of higher (initial) orbitOf transition producing this emission? c) If electron angular quantum number of initial state is s, what is orbital quantum number in final state?

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Answered: Light of wavelength of 102.6 nm is…

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