Light of a single wavelength is incident upon a diffraction grating that is 129 mm wide with 60,000 slits. The third order maximum (m3) has an angular position of 55° on the viewing screen placed 2.0 m away from the diffraction grating. What is the wavelength of the light (in units of nm) that is incident upon the diffraction grating? Please enter only the numerical value to the nearest whole integer, i.e., X, and do not include units.
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- A light of wavelength 700 nm illuminates a diffraction grating. 2nd order maximum is at 55°. What is the number of gratings per cm? 854.5 lines/cm 585.1 lines/cm 1709 lines/cm 85450 lines/cm 11702 lines/cm 5851.4 lines/cm 170900 lines/cmIn the figure, two radio-frequency point sources S1 and S2, separated by distance d = 1.6 m, are radiating in phase with A = 0.4 m. A detector moves in a large circular path around the two sources in a plane containing them. How many maxima does it detect? Number x S₁ S2 UnitsThe wavelengths of the visible spectrum are approximately 400nm (violet) to 700nm (red). Find the angular width of the first-order visible spectrum produced by a transmission diffraction grating with 405 lines per millimeter when white light falls normally on the grating.Give your answer in degrees.
- A 1.0-cm-wide diffraction grating has 1000 slits. It is illuminated by light of wavelength 550 nm. What are the angles of the first two diffraction orders?A red laser of wavelength 632.8x10-9 m is directed horizontally towards a diffraction grating. The separation between slits on the grating is 2.54x10-5 m. What angle is a 2nd order bright spot is seen at? Use the following equation to calculate the angle. mλ = d sin 0In an interference experiment using a monochromatic source emitting light of wavelength 1, the fringes are produced by two long, narrow slits separated by a distance d. The fringes are formed on a screen which is situated at a distance D >> d.Write down an expression for the fringe width w. Please use "*" for products (e.g. B*A), "/" for ratios (e.g. B/A) and the usual "+" and "-" signs as appropriate. Use "lambda" (without the quotes) for 1 in the equation box. For example, use d*lambda for d2. Please use the "Display response" button to check you entered the answer you expect. w=
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