A 1.0-cm-wide diffraction grating has 1000 slits. It is illuminated by light of wavelength 550 nm. What are the angles of the first two diffraction orders?
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A 1.0-cm-wide diffraction grating has 1000 slits. It is illuminated by light of wavelength 550 nm. What are the angles of the first two diffraction orders?
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- Irina finds an unlabeled box of fine needles, and wants to determine how thick they are. A standard ruler will not do the job, as each needle is less than a millimeter thick. So, to find the thickness, she uses a needle to poke a hole in a piece of brown construction paper. Then, she positions a 640 nm laser pointer to shine through the hole and project a circular diffraction pattern on a wall 20.2 m away. She then uses her ruler to measure that the central bright circle is 15.7 cm in diameter. What diameter does Irina calculate for the needle?A red laser of wavelength 632.8x10-9 m is directed horizontally towards a diffraction grating. The separation between slits on the grating is 2.54x10-5 m. What angle is a 2nd order bright spot is seen at? Use the following equation to calculate the angle. mλ = d sin 0The lens of a camera has a thin film coating designed to enhance the ability of the lens to absorb visible light near the middle of the spectrum, specifically light of wavelength 560 nm. If nair = 1.00, nfilmcoating %3D 1.40, and njens 1.55, what is the required minimum thickness of the film coating? Assume that the light is normally incident in the air medium. a. 200 nm O b.250 nm O c. 100 nm O d. 150 nm e. 300 nm
- A laser light source with wavelength λ = 545 nm is incident on a diffraction grating (as in the figure). The grating has 495 slits per mm. An observation screen is a distance L = 0.35 m from the grating. What is the separation between individual slits in the grating? Be careful with units: 1 nm = 10-9 m, 1 mm = 10-3 m, and 1 cm = 10-2 m. d = nm What is the distance y along the screen where the first-order diffraction peak is observed? y= cm source grating m=1Irina finds an unlabeled box of fine needles, and wants to determine how thick they are. A standard ruler will not do the job, as each needle is less than a millimeter thick. So, to find the thickness, she uses a needle to poke a hole in a piece of brown construction paper. Then, she positions a 670 nm laser pointer to shine through the hole and project a circular diffraction pattern on a wall 21.7 m away. She then uses her ruler to measure that the central bright circle is 15.7 cm in diameter. What diameter does Irina calculate for the needle? diameter: umYou measure three segments of the distance between a diffraction slit an the screen on which the pattern forms: x1 = (15.8 ± 0.2) cm, x2 = (6.7 ± 0.1) cm, and x3 = (11.3 ± 0.1). What is the uncertainty of the total distance x1 + x2 + x3? Group of answer choices 0.4 cm 0.5 cm 0.2 cm 0.3 cm 0.1 cm
- The figure shows two single-slit diffraction patterns. The distance between the slit and the viewing screen is the same in both cases. Which of the following could be true?A. The slits are the same for both; λ1 > λ2B. The slits are the same for both; λ2 > λ1C. The wavelengths are the same for both; a1 > a2D. The wavelengths are the same for both; a2 > a1Light of wavelength 633 nm is incident normally on a diffraction grating. The second-order maximum of the diffraction pattern is observed at 49.0°. a. What is the number of rulings per centimeter for the grating? b. Find the angle for the first-order maximum.Hi, can I please get some help with this question? Thank you!