Light-grade steel channel was used as a purlinof a truss. The top chord of the truss isinclined I V: 4 H and distance betweentrusses is equal to 6 m. The purlin has aweight of 79 N/m and spaced at 1.2 m. oncenters. The dead load including the roofmaterials is 720 Pa, live load of 1000 Pa andwind load of1.21.21440 Pa. Coefficient ofPurlinspressure at leeward and windward are 0.6 and0.2 respectively. Assume all loads passesthrough the centroid of the section.TrussProperties of C 200 x 76 mmSx = 6.19 x 104 mmSy = 1.38 x 104 mmW = 79 N/m12121.2 IAllowable bending stressFbx= Fby = 207 MPaTruss%3D6mO Calculate the bending stress, fox, for deadload and live load combination (D+ L).Calculate the bending stress, foy, for deadload and live load combination (D + L).O Calculate the maximum ratio of actual tothe allowable bending stress for loadcombination 0.75 (D + L + W) at thewindward side.fbx = 151.14 MPafby = 169.6 MPaInteraction = 1.25

Weight of the purlin = 79 N/m Dead load, DL = 720 N/m2 Live load, LL = 1000 N/m2 Wind load, WL =…

Light-grade steel channel was used as a purlin of a truss. The top chord of the truss is inclined IV: 4 H and distance between trusses is equal to 6 m. The purlin has a weight of 79 N/m and spaced at 1.2 m. on centers. The dead load including the roof materials is 720 Pa, live load of 1000 Pa and wind load of 1440 Pa. Coefficient of pressure at leeward and windward are 0.6 and 0.2 respectively. Assume all loads passes through the centroid of the section. Properties of C 200 x 76 mm Sx=6.19 x 104 mm³ Sy= 1.38 x 104 mm³ W = 79 N/m Allowable bending stress Fbx=Fby = 207 MPa Calculate the bending stress, fox, for dead load and live load combination (D+ L). Calculate the bending stress, foy, for dead load and live load combination (D+ L). 3 Calculate the maximum ratio of actual to the allowable bending stress for load combination 0.75 (D + L + W) at the windward side. 1.2 1.2 1.2 1.2 fbx = 151.14 MPa fby = 169.6 MPa Interaction = 1.25 Truss 1.2 6m Purlins Truss

Light-grade steel channel was used as a purlin of a truss. The top chord of the truss is inclined IV: 4 H and distance between trusses is equal to 6 m. The purlin has a weight of 79 N/m and spaced at 1.2 m. on centers. The dead load including the roof materials is 720 Pa, live load of 1000 Pa and wind load of 1440 Pa. Coefficient of pressure at leeward and windward are 0.6 and 0.2 respectively. Assume all loads passes through the centroid of the section. Properties of C 200 x 76 mm Sx=6.19 x 104 mm³ Sy= 1.38 x 104 mm³ W = 79 N/m Allowable bending stress Fbx=Fby = 207 MPa Calculate the bending stress, fox, for dead load and live load combination (D+ L). Calculate the bending stress, foy, for dead load and live load combination (D+ L). 3 Calculate the maximum ratio of actual to the allowable bending stress for load combination 0.75 (D + L + W) at the windward side. 1.2 1.2 1.2 1.2 fbx = 151.14 MPa fby = 169.6 MPa Interaction = 1.25 Truss 1.2 6m Purlins Truss

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Answer in hand written ty beed asap
Calculate and draw the internal forces created at H section of the bracket beam? a = 500 mm b= 200 mm Px= 15 Kn Py=0 Kn Pz = 10 Kn
A mechanical support framing system is shown below. The framing consists of steel floor grating over steel beams and entirely supported by four tension hangers that are connected to floor framing above it. It supports light machinery with an operating weight of 4000 lbs, centrally located. (a) Determine the impact factor I from the Live Load Impact Factor, (b) Calculate the total live load acting on one hanger due to the machinery and uniform live load of 40 psf around the machine. (c) Calculate the total dead load acting on one hanger. The floor framing dead load is 25 psf. Ignore the weight of the hangers. Lateral bracing is located on all four edges of the mechanical floor framing for stability and transfer of lateral loads.
solve for member BD and member AB Indicate clearly (tension or compression ) in final answer
4-5 The A-36 steel rod is subjected to the loading shown. If the cross-sectional area of the rod is 60 mm², determine the displacement of B and A. Neglect the size of the cou- plings at B, C, and D. 60° 3.30 KN 2 kN D C B A 8 kN 60⁰ 3.30 KN 0.75 m 1.50 m 0.50 m 2 kN
7-55. The member consists of two plastic channel strips 0.5in. thick, glued together at A and B. If the distributed load has a maximum intensity of w 3 kip/ft, determine the maximum shear stress resisted by the glue. 6 ft 6 ft 3 in. 3 in. 6 in.
Please help me. I will give a thumbs up. Thank you! A 25 m long girder of a bridge is simply supported at the right end and at 3 m from the left end. It is subjected to a highway lane-load consisting of a uniformly distributed load and a concentrated load as follows: Uniformly distributed live load = 10.55 kN/m Concentrated load = 69 kN What is the maximum moment at the middle of the supports in kN-m?
Question 10 options: a) 2.10 MPa b) 1.12 MPa c) 1.53 MPa d) 2.92 MPa
2. Determine the force in each member of the truss. IHG F D 2a L6@a²6a
PLEASE INCLUDE COMPLETE SOLUTION
The section of a Super-T prestressed concrete girder is shown below. The girder is simply supported on a span of 7.0 m and are pre-tensioned with total initial force of 825 kN from low-relaxation strands. The girder supports a total dead load of 2 kPa and live load of 6 kPa. There is a loss of prestress of 0.2 at service loads. Assume "-" for compression and "+" for tension. Hint: Assume tributary width is equal to flange width. Properties of the section: A = 100,000 mm2 INA = 940 x 106 mm4 All measurements in the drawings are in millimeters. 1. What is the stress, in MPa, at the top fibers of the girder at end span due to initial prestressing force only? 2. What is the stress, in MPa, at the bottom fibers of the girder at midspan due to initial prestressing force only? 3. What is the stress, in MPa, at the top fibers of the girder at end span due to prestressing force and service loads? 4. What is the stress, in MPa, at the bottom fibers of the girder at midspan due to prestressing…
A simply supported wood beam that is 13.5 m long carries a 36 kN concentrated load at B. The cross-sectional dimensions of the beam are b- 155 mm, d- 390 mm, a - 65 mm, and c- 30 mm. Section a-a is located at x- 2.3 m from B. (a) At section a-a, determine the magnitude of the shear stress in the beam at point H. (b) At section a-a, determine the magnitude of the shear stress in the beam at point K. (c) Determine the maximum horizontal shear stress that occurs in the beam at any location within the entire span. (d) Determine the maximum tensile bending stress that occurs in the beam at any location within the entire length. |P H d a В C L 2L 3 Answer: (a) TH - 0.33 kPa (b) TK - i 0.169 kPa (c) Tmax - 0.595 kPa (d) Omax" 27.486 MPa 3