Level 2 D 15. In the figure, ACEF is a straight line. It is given that AB = FD, BE = DC and AC = EF. AE = CF ACt CE= EF+CE - Ac= EF C Gue) CE E (a) Prove that AABE =)AFDC. (b) Prove that BC = DE.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.7: Applied Problems
Problem 21E
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9.56 Chapter 9
Level 2
15. In the figure, ACEF is a straight line. It is given that AB = FD,
BE = DC and AC = EF.
AE = CF
AC+ CE= EF tCE
- Ac- EF C Give)
CE
E
(a) Prove that A ABE
AFDC.
(b) Prove that BC = DE.
A
B
16. In the figure, AB = AC, AE = AD and ZCAB = LEAD.
DC= EB CG)
(a) Prove that ZCAE = 2BAD.
(b) Prove that AACE
CE EC
Transcribed Image Text:9.56 Chapter 9 Level 2 15. In the figure, ACEF is a straight line. It is given that AB = FD, BE = DC and AC = EF. AE = CF AC+ CE= EF tCE - Ac- EF C Give) CE E (a) Prove that A ABE AFDC. (b) Prove that BC = DE. A B 16. In the figure, AB = AC, AE = AD and ZCAB = LEAD. DC= EB CG) (a) Prove that ZCAE = 2BAD. (b) Prove that AACE CE EC
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