main.c 1. Leap Year Detector 1 #include by CodeChum Admin 2 3 int isleapYear(int); Let's try to find out whether a year has 365 or 366 days. To do this, we need to create a 5- int main(void) { leap year detector! // TODO: Write your code here 7 8 return 0; Conditions for a leap year: 9 } 1.) year must be divisible by 4 and not divisible by 100 2.) If year is divisible by 100, it must be divisible by 400 for it to be a leap year. 10 11- int isleapYear(int n) { if( (n % 4 == 0 && n % 100 != 0) |I (n % 100 == 0 && n % 400 == 0) 12- 13 14 15 - ) { Instructions: 16 return 1; } 17 1. You are provided with the isLeapYear() function which is already declared and defined for you. 18 19 return 0; 20 3 2. Your task is to ask the user for a year and then call the isLeapYear function to check whether the year is a leap year or not.

main.c 1. Leap Year Detector 1 #include by CodeChum Admin 2 3 int isleapYear(int); Let's try to find out whether a year has 365 or 366 days. To do this, we need to create a 5- int main(void) { leap year detector! // TODO: Write your code here 7 8 return 0; Conditions for a leap year: 9 } 1.) year must be divisible by 4 and not divisible by 100 2.) If year is divisible by 100, it must be divisible by 400 for it to be a leap year. 10 11- int isleapYear(int n) { if( (n % 4 == 0 && n % 100 != 0) |I (n % 100 == 0 && n % 400 == 0) 12- 13 14 15 - ) { Instructions: 16 return 1; } 17 1. You are provided with the isLeapYear() function which is already declared and defined for you. 18 19 return 0; 20 3 2. Your task is to ask the user for a year and then call the isLeapYear function to check whether the year is a leap year or not.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Instructions Insurance.java >- Terminal + 1 import java.util.Scanner; sandbox $ 0 2 class Insurance { The Harrison Group Life Insurance company computes public static void main (String args[]) { // Write your code here annual policy premiums based on the age the customer 4 turns in the current calendar year. The premium is } computed by taking the decade of the customer's age, adding 15 to it, and multiplying by 20. 7 public static int calculatePremium(int curr, int birth) { 8 // Write your code here } For example, a 34-year-old would pay $360, which is calculated by adding the decades (3) to 15, and then 10 } 11 multiplying by 20. Write an application that prompts a user for the current year then a birth year. Pass both to a method that calculates and returns the premium amount, and then display the returned amount. An example of the program is shown below: Enter the current year >> 2020 Enter the birth year >> 2001 The premium is $320 Grading Write your Java code in the area on the…
C++ A robot is initially located at position (0; 0) in a grid [?5; 5] [?5; 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move and the current position of the robot. If the robot makes a circle, which means it moves back to the original place, print "Back to the origin!" to the console and stop the program. If it reaches the boundary of the grid, print \Hit the boundary!" to the console and stop the program. A successful run of your code may look like:Down (0,-1)Down (0,-2)Up (0,-1)Left (-1,-1)Left (-2,-1)Up (-2,0)Left (-3,0)Left (-4,0)Left (-5,0)Hit the boundary! or Left (-1,0)Down (-1,-1)Right (0,-1)Up (0,0)Back to the origin! About: This program is to give you practice using the control ow, the random number generator, and output formatting. You may use <iomanip> to format your output. You may NOT use #include "stdafx.h".
my code is getting errors and i cant figiure out why , can you check my code and help me fix the errors . written in c code. It needs to print out a maze and as you hit enter you go through the maze. #include <stdio.h>#include <stdlib.h> #define XSTART 2#define YSTART 0 #define DOWN 0#define RIGHT 1 #define UP 2#define LEFT 3 void mazeTraverse(char maze [12][12],int xCor,int yCor,int dir);int checkForEdge(int x , int y);int correctMoves (char maze[][12],int r , int c );void displayMaze (char maze [][12]); int main (void){ char maze [12] [12] ={{'#','#','#','#','#','#','#','#','#','#','#','#'}, {'#','.','.','.','#','.','.','.','.','.','.','#'}, {'.','.','#','.','#','.','#','#','#','#','.','#'}, {'#','#','#','.','#','.','.','.','.','#','.','#'}, {'#','.','.','.','.','#','#','#','.','#','.','.'}, {'#','#','#','#','.','#','.','#','.','#','.','#'}, {'#','.','.','#','.','#','.','#','.','#','.','#'}, {'#','#','.','#','.','#','.','#','.','#','.','#'},…
Lab Goal : This lab was designed to teach you more about recursion. Lab Description : Take a number and recursively determine how many of its digits are even. Return the count of the even digits in each number. % might prove useful to take the number apart digit by digitSample Data : 453211145322224532714246813579Sample Output : 23540 I want a code class and a runner class without the scanner class
// Assume all libraries are included void QQ(int n); // int main () { // Random questions QQ (5) ; 3 4 6. 7 8. 9. 10 return 0; 11 } // void QQ(int n) 12 13 14 { if(n >= 1) { 15 16 17 cout << n; QQ (--n); } else 18 19 20 21 cout << n; 22 } // 23
How can I apply this python code? def createList(n): #Base Case/s #TODO: Add conditions here for your base case/s #if <condition> : #return <value> #Recursive Case/s #TODO: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once you've completed all the TODO for this function return [] def removeMultiples(x, arr): #Base Case/s #TODO: Add conditions here for your base case/s #if <condition> : #return <value> #Recursive Case/s #TODO: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once you've completed all the TODO for this function return [] def Sieve_of_Eratosthenes(list): #Base Case/s if len(list) < 1 : return list #Recursive Case/s else: return [list[0]] + Sieve_of_Eratosthenes(removeMultiples(list[0],…
int isbivisibley6(int num) (mu ) reture isDivisibleBy6( ); (num return 13 ( 1mum ) nUR num 10 ) return reture isDivisibleBy6( num/ 10 2 ( num num/10 sol) ); 12 ) 13 int main(O 14 ( int num 6003; (isDivisibleBy6( )) print ("Divisible" ); else print ("Not Divisible" ); return 0; 16 17 18 19 20 input Compilation taled due to foowing main.cif:10: error: too few arguments to function 'isDivisibleBy6' 6 return isDivisibleby6( ); main.cl: note: declared here 3| int isDivisibleBy6(int num) main.c: In function 'main': main.c:16:6: error: too few arguments to function 'isDivisibleBy6 16 | if( isDivisibleBy6( )) Apunun main.c3:5: note: declared here 3 int isDivisibleBy6(int num
Lab Goal : This lab was designed to teach you more about recursion. Lab Description : Take a number and recursively determine how many of its digits are even. Return the count of the even digits in each number. % might prove useful to take the number apart digit by digitSample Data : 453211145322224532714246813579Sample Output : 23540 I want a code class and a runner class
Part III - Create Your Own Art Art.java In this part you will create a program Art.java that produces a recursive drawing of your own design. This part is meant to be fun, but here are some guidelines in case you're not so artistic. Requirements Art.java must take one (1) integer command-line argument n that controls the depth of recursion. Your drawing must stay within the drawing window when n is between 1 and 7. (The autograder will not test values of n outside of this range.) You may not change the size of the drawing window (but you may change the scale). Do not add sound. Your drawing can be a geometric pattern, a random construction, or anything else that takes advantage of recursive functions. Your program must be organized into at least three separate functions, including main(). All functions except main() must be private. For full credit, Art.java must not be something that could be easily rewritten to use loops in place of recursion, and some aspects of the recursive…
#include <stdio.h> struct Single { int num; }; void printSingle(int f) { int binaryNum[33]; int i = 0; while(f>0) { binaryNum[i] = f % 2; f = f/2; i++; } for (int j=i-1; j>= 0; j--) { printf("%d",binaryNum[j]); } } int main() { struct Single single; single.num = 33; printf("Number: %d\n",single.num); printSingle(single.num); return 0; }
Write these in Pseudocode #1a – In pseudocode, write a call to a function that passes 1 Integer variable and 1 Integer array, and saves a Boolean value in return. #1b – In pseudocode, write the function that accepts 1 Integer and 1 Integer array and returns a Boolean. In the function, search the Integer array with a for-loop, and if the Integer parameter is found in the array, return false. If the Integer parameter is not found, return true. #2a – In pseudocode, write a call to a module that passes 1 Integer variable, 1 Real variable, 1 String constant, and 1 String literal as arguments. #2b – In pseudocode, write the module header that accepts 1 Integer, 1 Real, and 2 Strings as parameters. #3 – This pseudocode has multiple problems. Fix the calling statement and the definition below so that the routine accepts 3 grades as parameters and returns the average into a variable.…
#include<iostream>#include<math.h>using namespace std;class TotalResistance{double series_res,parallel_res,sp_res;public:TotalResistance(){series_res=parallel_res=sp_res=0;}void seriesResistance(double resistance[],int n);void parallelResistance(double resistance[],int n);void spResistance(double resistance[],int n);};void TotalResistance::seriesResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];cout<<"Total Resistance in series is: "<<series_res<<endl;}void TotalResistance::parallelResistance(double resistance[],int n){double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in parallel is: "<<parallel_res<<endl;}void TotalResistance::spResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in series…