Convert the binary output of the following program to base 10. int Digit-[L1, L2, L3, L4, LS, L6, L7, L8]; for (1-0; ic8, i++) if Digit(i]>3 Digit(i)-1; else Digit[1)-0;
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use with the L numbers being 20518040 instead of 1-8
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- Question: For every part that says "TODO" is a part you need to write. Correctly written code works if every "TODO" is written correctly. #include <stdio.h> void print_intbits(int num); int main(int argc, char *argv[]){int x; printf("x has only the 16th bit set\n");x = 1 << 16;print_intbits(x); printf("x as decimal: %d\n", x);printf("x as octal : %o\n", x);printf("x as hex : %x\n", x);printf("\n"); printf("set 19th bit as well\n");x = x | (1 << 19);print_intbits(x); printf("set 3rd bit as well\n");// TODO: set the indicate bit in x// ???print_intbits(x); printf("invert the bits\n");x = ~x;print_intbits(x); printf("clear the 8th bit\n");x = x & ~(1 << 8);print_intbits(x); printf("clear the 25th bit\n");// TODO: clear given bit in x// ???print_intbits(x); printf("clear all bits via xor\n");x = x ^ x;print_intbits(x); printf("place the pattern 110101 starting at bit 8\n");x = x | (0b110101 << 8);print_intbits(x); printf("place the pattern 10011111…@@@PROGRAM C int getNum(); /*accepts input from the user.*/ long decBin(int n); /* returns the binary equivalent of n. Note: Use of built in functions that will automatically convert decimal to binary is not allowed. */ void display(long binary); /*displays the binary equivalent*/ ------------------------------------------------------------------------
- Write a function that parses a binary number into a hex number.The function header is:def binaryToHex(binaryValue):Write a test program that prompts the user to enter a binary number and displays the corresponding hexadecimal value.Write a function that prints the ASCII values of the char- acters using the following header: void printASCII(char ch1, char ch2, int numberPerLine) This function prints the ASCII values of characters between ch1 and ch2 with the specified number of characters per line. Write a test program that prints 6 ASCII values per line of characters from 'a' to 'm'.pio l Jg Slogle X Quiz: FinalExam e/quizzes/4585/ake/questions/74432 Study the definitions of function "get" and answer the question below Note: ASCII Code for A= '65' , B='66', H='72',a='9 7', h='104' int get (int x, char y, double z){ if ( (x - y) > 0) return ( (static_cast(y) - 65)); else return (y + x ); double get (double x,int z,char y) { return ( static_cast(y)); char get (char x,int y,double z){ x = static cast( y + ceil (z)); return x; What is the output of the following code segment? cout<The program below stores 80 bool values into a char arr[10]. CompletesetBool and getBool. In both functions, index is the index of the boolvalues, from 0 to 79. getBool returns 1 if the bool value at index is trueotherwise 0. You will probably need most bitwise operations including shifting. void setBool ( char * arr , int index , int boolValue ) {}int getBool ( char * arr , int index ) {}int main ( void ) {char arr [10];memset ( arr , 0 , 10);setBool ( arr , 78 , 1);setBool ( arr , 40 , 0);int b78 = getBool ( arr , 78); // b78 is 1int b40 = getBool ( arr , 40); // b40 is 0return 0;}Q. modify the Code Using set and test or swap? #include <stdio.h>#include <stdlib.h>#include <pthread.h> long long sum=0,num=2000000; pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER; void *mySumFun(void *vargp){int step=*(int *) vargp; for(int i=0;i<num;i++){//pthread_mutex_lock(&mutex);sum+=step;// pthread_mutex_unlock(&mutex);}return NULL;}int main(){pthread_t tid1,tid2;int step1=1, step2=-1;pthread_create(&tid1, NULL, mySumFun, &step1); pthread_create(&tid2, NULL, mySumFun, &step2);pthread_join(tid2, NULL);pthread_join(tid1, NULL);printf("The sum is = %lld \n", sum);exit(0);}Rrffddx#include <stdio.h> #include <stdlib.h> double f(double x){ return x*x; } double reimannSums(double f(double), double a, double b, int n, double deltax) double sum=0.0, x; int i; printf("n = %d\n",nvoidvoid); for (i=0;i<n;i++){ x= ( (a+i*deltax)+a+(i+1)*deltax))/2; printf("x = %lf\n,x"); sum=sum + f(x); } return sum = (sum * deltax); double integ(double a, double b, double deltax) { double result; int n; n = (b - a) / deltax; return reimannSums(f, a, b, n, deltax); } int main(int argc, char * argv[]) { int a = atoi(argv[1]); int b = atoi(argv[2]); double deltax = atof(argv[3]); printf("result= %lf",integ(a, b, deltax)); } CAN YOU PLEASE CHECK MY WORK I GOT BUILD FAILED ERROR C LANGUAGE I NEED ANSWER IN 30 MIN THANKS<3#take inputh=int(input("Enter height of triangle: "))c=input("Enter character: ") #check for -ve hif h<=0: h=3 #check for c#remove whitespacesc=c.replace(" ","")#if c has no or multiple charactersif c=="": c="*"if len(c)>1: c=c[0] #print triangle#if height is only 1if h==1: print(c) else: s1=h-1 s2=0 for i in range(s1): print(end=" ") print(c) s1-=1 s2+=1 for i in range(2,h): for j in range(s1): print(end=" ") print(c,end="") for k in range(s2): print(end=" ") print(c,end="") s1-=1 s2+=2 print() print(c,end="") for i in range(s2): print(c,end="") print(c,end="") print("") How can I move the triangle to the right with this code? How canI fix it?Please explain the coding. Screen shot the code and the output.SEE MORE QUESTIONS