Let's say your current programming project is using a circular queue implementation which uses a simple modulus operation for moving the head and tail forward: p = (p+1)%n. But the queue isn't a purely traditional one and you sometimes have to move backwards during a search. When this search wraps from the front to the rear, you must use this code: p = (p==0?n-1:p-1). One day programmer Sam comes up with this little gem: p=(p+d)%n. Here d is filled in with 1 when moving forward and n-1 when moving backwards. Can Sam's simple solution be correct? Prove or disprove Sam here.
Let's say your current programming project is using a circular queue implementation which uses a simple modulus operation for moving the head and tail forward: p = (p+1)%n. But the queue isn't a purely traditional one and you sometimes have to move backwards during a search. When this search wraps from the front to the rear, you must use this code: p = (p==0?n-1:p-1). One day programmer Sam comes up with this little gem: p=(p+d)%n. Here d is filled in with 1 when moving forward and n-1 when moving backwards. Can Sam's simple solution be correct? Prove or disprove Sam here.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Let's say your current programming project is using a circular queue implementation which uses a simple modulus operation for moving the head and tail forward: p = (p+1)%n. But the queue isn't a purely traditional one and you sometimes have to move backwards during a search. When this search wraps from the front to the rear, you must use this code: p = (p==0?n-1:p-1). One day programmer Sam comes up with this little gem: p=(p+d)%n. Here d is filled in with 1 when moving forward and n-1 when moving backwards. Can Sam's simple solution be correct? Prove or disprove Sam here.
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