Let's define the random variable X to be the number of goals scored by a randomly selected team in a randomly selected game. The table below gives theprobability distribution of X:Goals:0edC179Probability: 0.061 0.154 0.228 0.229 0.173 0.094 0.041 0.015 0.004 0.001a. Compute the expected value of the random variable X.E(X)= type your answer....C$b. Compute the standard deviation of the random variable X.SD (X)= type your answer...42Lf3un do%5goals4goalstg>5<106JULb6DELLyhV &8JUj8i9k0VCO1alt31Pctri

Mean(μ)=E(X)=∑x.P(X)E(X2)=∑x2.P(X)variance(σ2)=E(X2)-(E(X))2Standard deviation(σ)=E(X2)-(E(X))2

Let's define the random variable X to be the number of goals scored by a randomly selected team in a randomly selected game. The table below gives the probability distribution of X: 4 5 7 Probability: 0.061 0.154 0.228 0.229 0.173 0.094 0.041 0.015 0.004 0.001 Goals: 0 1 2 3 a. Compute the expected value of the random variable X. E(X)= type your answer..... b. Compute the standard deviation of the random variable X. SD (X)= type your answer..... goals goals 6 8 9

Let's define the random variable X to be the number of goals scored by a randomly selected team in a randomly selected game. The table below gives the probability distribution of X: 4 5 7 Probability: 0.061 0.154 0.228 0.229 0.173 0.094 0.041 0.015 0.004 0.001 Goals: 0 1 2 3 a. Compute the expected value of the random variable X. E(X)= type your answer..... b. Compute the standard deviation of the random variable X. SD (X)= type your answer..... goals goals 6 8 9

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

The probability distribution for the random variable, x, is x:2, 2.5,3.0,3.5,4.0 ,4.5 and P(x):0.07, 0.36, 0.21, 0.19, 0.10, 0.07 Calculate P(x >= 3.0) a. 0.57 O b. 0.19 O C. 0.83 d. 0.47 O
The following table represents the joint probability distribution of the number of people waiting in line at Food Truck X and Food Truck Y. Y=0 Y=1 Y=2 Y=3 PX(X=x) X=0 0.32 0.06 0.025 0.01 X=1 0.02 0.05 0.07 X=2 0.025 0.05 0.105 X=3 0.026 0.2 0.05 0.024 PY(Y=y) 0.114 a. Determine the probability of 3 people waiting in line at Food Truck Y and 2 people waiting in line at Food Truck X. b. What is the probability of at most 3 people waiting in line at both Food Truck X and Y combined? c. If at least 2 people are waiting in line at Food Truck X, what is the probability that 3 people are waiting in line at Food Truck Y?
The probability distribution of the number of students absent on Mondays, is as follows: X O 1 2 3 4567 f(x) 0.02 0.03 0.26 0.34 0.22 0.08 0.04 0.01 (a) What is the probability that more than 3 students are absent. (b) Compute the expected value of the random variable X. Interpret this expected value. (c) Compute the variance and standard deviation of the random variable X. (d) Compute the expected value and variance of Y : (e) Compute the covariance Cov(X, Y) = 7X+ 3. (f) What is the value of the ratio Cov(X,Y)/Var(X) ? (g) What is the value of Cov(X, Y)/Var(X) for Y = ß0 + ß₁X ? (For this exrcise, you can use excel. No need to show all calculations, just specify the formulas and present the final values.) (a) (b) (c) (d) (e) (f) (g)
The joint probability distribution for the Random variable X and Y is shown below where X = the number of Strawberry ice-cream cones in the freezer Y = the number of Chocolate ice-cream cones in the freezer y p(x, y) 1 2 .025 .015 .010 .050 .030 .020 .075 090 .125 .050 150 060 012
The probability distribution of the random variable X represents the number of hits a baseball player obtained in a game for the 2012 baseball season. 1 2 3 4 P(x) 0.1666 0.3437 0.2774 0.1486 0.0384 0.0253
The probability distribution of random variable X is defined as follows: X 0 1 2 3 4 Probability 0 0.3 0.1 0.3 0.3 Find the expected value and the standard deviation of X.
The random variable X has the probability distribution given in the following table. 1 2 3 4 5 P(X = x) 0.03 0.27 where a, b and e are constants. It is given that E(X) = 3.5 and Var(X) = 1.17. Find the values of a, b and c.
For familiés with 5 children, let X be the number of children with Genetic Condition B. Can the following table be a probability distribution for the random variable X? P(x) 1 0.2862 0.0776 3. 0.1155 4 0.0491 0.3974 O no O yes 2.
High school students in Michigan sometimes get "snow days" in the winter when the roads are so bad that school is canceled for the day. Define the random variableX = the number of snow days at a certain high school in Michigan for a randomly selected school year. Suppose the table below gives the probability distribution of X. 1. Value x, 1. 3 4 5 6 7 8 9 10 Probability p, ? 0.19 0.14 0.10 0.07 0.05 0.04 0.04 0.02 0.01 0.01 (a) Write the event “the school year has O snow days" in terms of X. Then find its probability. (b) At this high school, if more than 5 snow days are used over the course of the year, students are required to make up the time at the end of the school year. What's the probability that a randomly selected school year will require make-up days?
The probability distribution of random variable, X, is defined as follows: X 0 1 2 3 4 Probability 0 .3 .1 .3 .3 The P(X = 0) =?
Let discrete random variables X and Y have the following probability distribution: Y 1 -1 0.10 0.18 0.10 X 0.09 0.15 0.23 1 0.03 0.05 0.07 Find the E(X2 Y²) -0.91 1.18 0.91 1.0494