Let's call the initial temperature T1 = 290 K, and so the initial pressure is P1 = 1.80 ✕ 106 Pa. The final temperature is then T2 = 330 K. Calculate the final pressure. (Reminder—use the letter "e" to express scientific notation in your response. For example, if your answer is 1.2 ✕ 104, enter it as 1.2e4.) P2 = _________ Pa Let's try another example. Suppose we now have a gas initially at a pressure of 1.30 ✕ 106 Pa and a temperature of 400 K. The gas is in a cylinder with an adjustable piston sealing it in. We then reduce the volume of the container to one-third 1 3 of its original value, but maintain a constant pressure of 1.30 ✕ 106 Pa. What is the new final temperature (in K) of the gas? _______ K
Let's call the initial temperature T1 = 290 K, and so the initial pressure is P1 = 1.80 ✕ 106 Pa. The final temperature is then T2 = 330 K. Calculate the final pressure. (Reminder—use the letter "e" to express scientific notation in your response. For example, if your answer is 1.2 ✕ 104, enter it as 1.2e4.) P2 = _________ Pa Let's try another example. Suppose we now have a gas initially at a pressure of 1.30 ✕ 106 Pa and a temperature of 400 K. The gas is in a cylinder with an adjustable piston sealing it in. We then reduce the volume of the container to one-third 1 3 of its original value, but maintain a constant pressure of 1.30 ✕ 106 Pa. What is the new final temperature (in K) of the gas? _______ K
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter5: Gases
Section: Chapter Questions
Problem 23QAP: Helium-filled balloons rise in the air because the density of helium is less than the density of...
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Let's call the initial temperature
T1 = 290 K,
and so the initial pressure is
P1 = 1.80 ✕ 106 Pa.
The final temperature is then
T2 = 330 K.
Calculate the final pressure. (Reminder—use the letter "e" to express scientific notation in your response. For example, if your answer is 1.2 ✕ 104, enter it as 1.2e4.)P2 = _________ Pa
Let's try another example. Suppose we now have a gas initially at a pressure of 1.30 ✕ 106 Pa and a temperature of 400 K. The gas is in a cylinder with an adjustable piston sealing it in. We then reduce the volume of the container to one-third
of its original value, but maintain a constant pressure of 1.30 ✕ 106 Pa. What is the new final temperature (in K) of the gas?
1 |
3 |
_______ K
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