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Let x[n]={0,1, 2, 3, -1}, then the DTFT of x[n] %3D a)X(jø) = cos(@) +2 cos(2@) +3cos(3@) – cos(4@) – j(sin(@) +2 sin(2@)+3 sin(3@) – sin(4@)) b)X(jø) = cos(@) +2 cos(2@)+3cos(3@) – cos(4@) – j(sin(@) +2 sin(2@) +3 sin(3@) +4 sin(4@)) c)X(j@) =1+2cos(@)+3cos(2@)+cos(3@) – j(2sin(@)+3sin(2@) – sin(30)) d)X(jø) =1+2cos(@) +3cos(2@) – cos(3@) – j2 sin(@) – j3sin(2@) + j sin(3@)) a

Let x[n]={0,1, 2, 3, -1}, then the DTFT of x[n] %3D a)X(jø) = cos(@) +2 cos(2@) +3cos(3@) – cos(4@) – j(sin(@) +2 sin(2@)+3 sin(3@) – sin(4@)) b)X(jø) = cos(@) +2 cos(2@)+3cos(3@) – cos(4@) – j(sin(@) +2 sin(2@) +3 sin(3@) +4 sin(4@)) c)X(j@) =1+2cos(@)+3cos(2@)+cos(3@) – j(2sin(@)+3sin(2@) – sin(30)) d)X(jø) =1+2cos(@) +3cos(2@) – cos(3@) – j2 sin(@) – j3sin(2@) + j sin(3@)) a

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Let x[n]={0,1, 2, 3, -1}, then the DTFT of x[n] %3D a)X(jø) = cos(@) +2 cos(2@) +3cos(3@) – cos(4@) – j(sin(@) +2 sin(2@) +3 sin(3@) – sin(4o)) b)X(jø) = cos(@) +2 cos(2@)+3cos(3@) – cos(4@) –j(sin(@)+2 sin(2@)+3 sin(3@) +4 sin(4@)) c)X(jø) =1+2cos(@) +3 cos(2@) +cos(3@) – j(2sin(@)+3sin(2@) – sin(3@)) d)X(jø) =1+2cos(@)+3cos(2@) - cos(3@) – j2 sin(@) – j3sin(2@) + j sin(3@)) d
Transcribed Image Text:Let x[n]={0,1, 2, 3, -1}, then the DTFT of x[n] %3D a)X(jø) = cos(@) +2 cos(2@) +3cos(3@) – cos(4@) – j(sin(@) +2 sin(2@) +3 sin(3@) – sin(4o)) b)X(jø) = cos(@) +2 cos(2@)+3cos(3@) – cos(4@) –j(sin(@)+2 sin(2@)+3 sin(3@) +4 sin(4@)) c)X(jø) =1+2cos(@) +3 cos(2@) +cos(3@) – j(2sin(@)+3sin(2@) – sin(3@)) d)X(jø) =1+2cos(@)+3cos(2@) - cos(3@) – j2 sin(@) – j3sin(2@) + j sin(3@)) d
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