Let X ~ N(μx, o) and Y ~ N(µy, o?). Suppose we are given the following indepen- dently sampled data for X and Y³: sample for X sample for Y : 24.8 12.8 11.1 11.1 15.9 12.2 18.3 8.9 5.6 12.8 17.3 11.3 : 26.6 26.3 25.2 23.3 22 20.2 26.1 21.1 14.6 14.5 21.8 22.8 21.5 22.3 31 11.5 Compute a 95% confidence interval of μx - μy (i) using the knowledge that o = o} = 4.7; (ii) assuming we do not know the values of ox, oy, but we still know that ox = 0y = 0 for some unknown σ.
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- 9. What is the expression or formula for sample correlation coefficient rxy? For the data set below (table 1), solve for the sum of products for x and y, or Sxy. (see attached picture)Thirty Asian Utility vehicles were tested for biodiesel fuel efficiency (in km/liter). The following frequency distribution was obtained Calculate the exact kurtosis (population) and excess kurtosis of the population (+ interpretation), sample kurtosis for this grouped data.An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range: 416 421 422 423 426 428 430 434 437 439 446 447 449 453 456 462 464 Comment on any interesting features. (Select all that apply.) ___The data appears to be centered near 438. ___There are no outliers. ___There is little or no skew. ___There is one outlier. ___The data is strongly skewed. ___The data appears to be centered near 428 Calculate a two-sided 95% confidence interval for true average degree of polymerization. (Round your answers to two decimal places.) (____, ____)
- Answer!!A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =can you please help me solve sub-parts e, f, g
- "1ÄUZ☺ 8:17 K/s You Just now 1. Consider the data below. This data represents the number of miles per gallon that 30 selected four-wheel drive sports utility vehicles obtained in city driving 12 17 16 | 14 16 18 16 18 17 16 17 15 15 16 16 15 16 19 10 14 15 11 15 15 19 13 16 |18 16 20 i) Calculate mean (Using Direct and Indirect method), median and mode of ungrouped data.1. A study compared the number of tree species in unlogged forest plots to similar plots logged 8 years earlier. Independent random samples of both logged and unlogged plots were analyzed and the number of tree species was recorded. Tables 1 and 2 present the Shapiro-Wilk normality test for both types of forest plots and the Independent Samples t-test results. Use the information presented in these tables to answer the questions. Table 1: Tests of Normality Tests of Normality Kolmogorov-Smirnov Shapiro-Wilk Forest Plot Statistic df Sig. Statistic df Sig. Tree_Species Logged .181 12 .200 .936 12 .444 Unlogged .110 14 .200 .945 14 .480 *. This is a lower bound of the true significance. a. Lilliefors Significance Correction Table 2: Independent Samples Test Independent Samples Test Levene's Test for Equality of Variances t-test for Equality of Means 95% Confidence Interval of the Difference Mean Std. Error F Sig. t df Sig. (2-tailed) Difference Difference Lower Upper Equal variances…For the following table, the ascending order (saclaill ijill) of samples and their data spread is: Sample R Mean 4.5 5.1 4.9 Variance 100 100 100 ORYou wish to test the claim that the first population mean is not equal to the second population mean at a significance level of α=0.02 . Ho:μ1=μ2 Ha:μ1≠μ2 You obtain the following two samples of data. Sample #1 Sample #2 67.1 64.2 32.7 49.0 63.8 54.8 63.5 54.1 65.6 54.8 40.5 58.7 39.4 43.1 72.5 73.1 70.2 71.2 68.1 73.1 79.7 67.3 66.5 61.7 62.9 76.5 What is the test statistic for this sample?test statistic = Round to 3 decimal places. What is the p-value for this sample?p-value = Use Technology Round to 4 decimal places. The p-value is... less than (or equal to) α greater than α This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean. There is not sufficient…The following information represents chlorine residuals in swimming pool (y) and the testing time (y) in different hours: n = 6, Ey = 8.8, Ey = 18.68, Ex = 42, Ex2 = 364, and Exy = 48.6 The sample correlation coefficient is: -0.6467 - 0.9899 - 0.9088 0.6467You wish to test the following claim (Ha) at a significance level of a = 0.01. H₂:μ₁ = μ₂ Ha:μι > με You obtain the following two samples of data. Sample #1 Sample #2 60 50.1 91.5 89.8 56 44.8 85.6 93.4 58.4 83.8 106.9 73.9 44.8 78.1 70.8 37.7 63.5 82.7 71.7 34.7 90.6 67.7 66.8 61.6 65 65.9 77.6 61.1 111.7 106.9 51.8 88.3 69 80.5 78.1 62.6 99.7 64.5 67.2 52.6 71.2 75.3 76.2 96.8 70.8 49.2 46.1 111.7 51.8 The p-value is... mlm What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = 66.2 63.3 60 63.1 61.3 75 62.3 63.3 69.4 57.9 71.2 68.4 74.7 70.6 65.1 68.5 75.8 78.4 73.1 58.6 59.1 66 71.5 67.2 67.3 69 70.9 68.9 73.1 64.4 66.9 71.2 65.6 68.7 60.7 65.3 76.3 74.7 70.1 65.6 59.6 68.2 67.2 69.7 68.9 65.4 66.2 65.6 65.1 62.5 0.7 60.4 68.9 76.8 65.6 76.3 64.7 55.6 71.7 69.7 64.2 72.9 What is the p-value for this sample? For this calculation, use the degrees of freedom reported from the technology you are using. (Report answer accurate to…SEE MORE QUESTIONS