Let X have binomial distribution with parameters n and p, find E( 1 /1 + X ) = E(  integral 0 to 1 Xdt) and find the limit of this expectation as n goes to 1 and p goes to  0, the limit is taken in such a way that np  goes to lamda  where 0 < lamda< 1. Comment

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Chapter1: Combinatorial Analysis
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Let X have binomial distribution with parameters n and p, find

E( 1 /1 + X ) = E(  integral 0 to 1 Xdt)

and find the limit of this expectation as n goes to 1 and p goes to  0, the limit is taken in such a way that np  goes to lamda  where 0 < lamda< 1. Comment

1
E(-
1+X
)= E(*dt)
Transcribed Image Text:1 E(- 1+X )= E(*dt)
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