Let X be the number of widgets that are defective when 3 widgets are randomly chosen and observed. The possible values for X are {0, 1, 2, 3}. The probability mass function for X is as follows. |  X  | f(x) = P(X = x) | |  0  |       0.550      | |  1  |       0.250      | |  2  |       0.175      | |  3  |       0.025      | Find: - E(X) - Var(X) - F(1) - F(2) - F(3)

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