Let X be a random variable with the following probability distribution.Value x of X P (X=x)200.10300.05400.70500.15Complete the following. (If necessary, consult a list of formulas.)(a) Find the expectation E (X) of X.E (x) = [](b) Find the variance Var(X) of X.Var(X) = []

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Answered: Let X be a random variable with the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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variable with the following probability distribution. Value x of X P=Xx -20 0.10 -10 0.15 0 0.45 10 0.25 20 0.05 Complete the following. (If necessary, consult a list of formulas.) (a) Find the expectation EX of X . ? =EX (b) Find the variance Var X of X .? =VarX
Let X be a random variable with the following probability distribution. Value x of X P(X=x) -30 0.05 -20 0.20 -10 0.15 0.20 10 0.40 Complete the following. (If necessary, consult a list of formulas.) |(a) Find the expectation E (X) of X. E (x) = 0 (b) Find the variance Var(X) of X. Var(x) = 0
Let X be a random variable with the following probability distribution. Value X of X P(X=x) 30 Continue 40 50 60 70 80 0.15 0.25 0.20 0.10 0.15 0.15 Complete the following. (If necessary, consult a list of formulas.) (a) Find the expectation E (X) of X. E (X) = (b) Find the variance Var(X) of X. Var(x) = 0 O S
A man has seven keys on a key ring, one of which fits the door he wants to unlock. He randomly selects a key and tries it. If it does not unlock the door, he randomly selects another key from those remaining and tries to unlock the door with it. He continues in this manner until the door is unlocked. Let X be the number of keys he tries before unlocking the door, counting the key that actually worked. Find the expected value and the standard deviation of X.
Let X be a random variable with the following probability distribution. Value x of X P(X=x) 10 20 30 40 50 0.10 0.30 0.20 0.25 0.15 Complete the following. (If necessary, consult a list of formulas.) (a) Find the expectation E (X) of X. E (X) = 0 (b) Find the variance Var(X) of X. Var(x) =
Let X be a random variable with the following probability distribution. Value x of X P(X=x) 2 0.05 3 0.05 4 0.05 5 0.85 Complete the following. (If necessary, consult a list of formulas.) (a) Find the expectation E(X) of X. E (X) = 0 (b) Find the variance Var(X) of X. Var(x) = ☐ Check B X G
In an uncertain economy, Americans tend to keep spending down. Let x be the amount of money U.S. individuals spend on groceries monthly. Suppose the probability distribution of x is a uniform distribution from $300 to $400 which is represented by the picture below. f(x) 0.010 0.008 0.006 0.004 0.002 300 320 340 360 380 400 X i (a) What is the probability that a randomly selected individual spends between $315 and $370 on groceries each month? (b) Determine whether the following statement is true or false. The variable, the amount an individual plans to spend on groceries per month, is a numerical (quantitative) variable. True O False
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An unfair die looks like an ordinary six-sided die but the outcomes are not equally likely. The probability distribution of the face value, XX, is as follows: xixi 1 2 3 4 5 6 Total P(X=xi)P(X=xi) 0.15 0.16 0.33 0.2 0.11 0.05 1 The expected value is computed, E[X]=3.11E[X]=3.11. To find the variance and standard deviation the following table was set up: xixi P(X=xi)P(X=xi) (xi−E[X])2(xi-E[X])2 (xi−E[X])2P(X=xi)(xi-E[X])2P(X=xi) 1 0.15 (1−3.11)2=(−2.11)2=4.4521(1-3.11)2=(-2.11)2=4.4521 4.4521⋅0.15=0.66784.4521⋅0.15=0.6678 2 (2−3.11)2=(−1.11)2=1.2321(2-3.11)2=(-1.11)2=1.2321 1.2321⋅0.16=0.19711.2321⋅0.16=0.1971 3 0.33 (3−3.11)2=(−0.11)2=(3-3.11)2=(-0.11)2= 0.0121⋅0.33=0.0040.0121⋅0.33=0.004 4 0.2 (4−3.11)2=(0.89)2=0.7921(4-3.11)2=(0.89)2=0.7921 0.7921⋅0.2=0.7921⋅0.2= 5 (5−3.11)2=(1.89)2=3.5721(5-3.11)2=(1.89)2=3.5721 3.5721⋅0.11=0.39293.5721⋅0.11=0.3929 6 0.05 8.3521⋅0.05=0.41768.3521⋅0.05=0.4176 E[X]=3.11E[X]=3.11 Total:…
Let Xbe a random variable with the following probability distribution. Question table Value of X P( X=x) 0 0.05 10 0.40 20 0.20 30 0.10 40 0.25 A. Find the expectation E(X) of (X) E(X)=? B. Find the variance VAR(X) of (X) VAR(X)=?
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Let X be a random variable with the following probability distribution. Value x of X P (X=x) 20 0.10 30 0.05 40 0.70 0.15 Complete the following. (If necessary, consult a list of formulas.) (a) Find the expectation E (X) of X. E (x) = ] %3D (b) Find the variance Var(X) of X. Var(x) = ] 50