Let x be a hypergeometric random variable with N = 12, n = 3, and M = 5. Use the formulas given below to calculate μ = E(x) and ². (Round your answer for ² to five decimal places.) n (M) N % I μl = n N-MY o² = n (M) (^~^) (N = 7) N N -

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Let \( x \) be a hypergeometric random variable with \( N = 12 \), \( n = 3 \), and \( M = 5 \).

Use the formulas given below to calculate \( \mu = E(x) \) and \( \sigma^2 \). (Round your answer for \( \sigma^2 \) to five decimal places.)

\[
\mu = n \left( \frac{M}{N} \right)
\]

\[
\sigma^2 = n \left( \frac{M}{N} \right) \left( \frac{N - M}{N} \right) \left( \frac{N - n}{N - 1} \right)
\]

\[
\mu = \text{{\_\_\_}}
\]

\[
\sigma^2 = \text{{\_\_\_}}
\]
Transcribed Image Text:Let \( x \) be a hypergeometric random variable with \( N = 12 \), \( n = 3 \), and \( M = 5 \). Use the formulas given below to calculate \( \mu = E(x) \) and \( \sigma^2 \). (Round your answer for \( \sigma^2 \) to five decimal places.) \[ \mu = n \left( \frac{M}{N} \right) \] \[ \sigma^2 = n \left( \frac{M}{N} \right) \left( \frac{N - M}{N} \right) \left( \frac{N - n}{N - 1} \right) \] \[ \mu = \text{{\_\_\_}} \] \[ \sigma^2 = \text{{\_\_\_}} \]
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