Let Us Try The employees of a manufacturing company pledged the following donations in peso for the establishment of a community pantry: 100, 400, 250, 50, 200, 300, 100, 50, 150, 250, 500, 100, 300, 50, and 150. Using the employees' contributions, calculate and interpret the following: a.) upper quartile b.) 7th decile Solution: c.) 35th percentile 50, 50, 50, 100, 100, 100, 150, 150, 200, 250, 250, 300, 300, 400, 500 a. Upper quartile or Q3 Qk = (n + 1) Q3 =(15 + 1) =(16) === 12 Q3 is in the 12th position. Therefore, Q3 = 300. b. 7th decile or D, 48 Dg = (n + 1) D, = (15 + 1) =(16) =- 112 = 11.2 10 10 10 10 Interpolate: 11.2nd position is between the 11th and 12th position which are 250 and 300, respectively. 300-250=50 then 250+0.2=250.2. Hence, D7=250.2 c. 35th percentile or P35 습(n + 1) Pss 3D 5(15 + 1) 3D(16)3 2-5.6 PR 100 100 Interpolate: 5.6th position is between the 5th and 6 position which are 100 and 100, respectively. Hence, Pas=100. Guide Questions: 1. How did you determine the value of the upper quartile, 7th decile and the 35* percentile? 2. How will you interpret the results?

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The employees of a manufacturing company pledged the following donations in peso
for the establishment of a community pantry: 100, 400, 250, 50, 200, 300, 100, 50, 150, 250,
500, 100, 300, 50, and 150. Using the employees' contributions, calculate and interpret the
following:
a.) upper quartile
Solution:
c.) 35th percentile
b.) 7th decile
50, 50, 50, 100, 100, 100, 150, 150, 200, 250, 250, 300, 300, 400, 500
a. Upper quartile or Q3
Qu = (n + 1) Q3 = (15 + 1) = (16) = = 12
Q3 is in the 12th position. Therefore, Q3 = 300.
b. 7th decile or D,
48
DR = (n + 1) D, = 2(15 + 1) =(16) = = 11.2
10
10
10
10
Interpolate: 11.2nd position is between the 11th and 12th position which are 250 and
300, respectively. 300-250=50 then 250+0.2=250.2. Hence, D7=250.2
c. 35th percentile or P35
(n + 1) P35 =
112 = 5.6
35
PR
(15 + 1) = (16) =
100
100
20
Interpolate: 5.6th position is between the 5th and 6th position which are 100 and 100,
respectively. Hence, P33=100.
Guide Questions:
1. How did you determine the value of the upper quartile, 7th decile and the 35th
percentile?
2. How will you interpret the results?
Transcribed Image Text:Let Us Try The employees of a manufacturing company pledged the following donations in peso for the establishment of a community pantry: 100, 400, 250, 50, 200, 300, 100, 50, 150, 250, 500, 100, 300, 50, and 150. Using the employees' contributions, calculate and interpret the following: a.) upper quartile Solution: c.) 35th percentile b.) 7th decile 50, 50, 50, 100, 100, 100, 150, 150, 200, 250, 250, 300, 300, 400, 500 a. Upper quartile or Q3 Qu = (n + 1) Q3 = (15 + 1) = (16) = = 12 Q3 is in the 12th position. Therefore, Q3 = 300. b. 7th decile or D, 48 DR = (n + 1) D, = 2(15 + 1) =(16) = = 11.2 10 10 10 10 Interpolate: 11.2nd position is between the 11th and 12th position which are 250 and 300, respectively. 300-250=50 then 250+0.2=250.2. Hence, D7=250.2 c. 35th percentile or P35 (n + 1) P35 = 112 = 5.6 35 PR (15 + 1) = (16) = 100 100 20 Interpolate: 5.6th position is between the 5th and 6th position which are 100 and 100, respectively. Hence, P33=100. Guide Questions: 1. How did you determine the value of the upper quartile, 7th decile and the 35th percentile? 2. How will you interpret the results?
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