Let S represent the amount of steel produced (In tons). Steel production is related to the amount of labor used (L) and the amount of capital used (C) by the following function. S = 20L0.30 0.70 In this formula L represents the units of labor input and C the units of capital input. Each unit of labor costs $50, and each unit of capital costs $100. (a) Formulate an optimization problem that will determine how much labor and capital are needed in order to produce 45,000 tons of steel at minimum cost. Min s.t. L, C20 $ = 45,000 (b) Solve the optimization problem you formulated in part (a). (Hint: When using Excel Solver, start with an initial L> 0 and C> 0. Round your answers to the nearest Integer.) at (L, C) =
Let S represent the amount of steel produced (In tons). Steel production is related to the amount of labor used (L) and the amount of capital used (C) by the following function. S = 20L0.30 0.70 In this formula L represents the units of labor input and C the units of capital input. Each unit of labor costs $50, and each unit of capital costs $100. (a) Formulate an optimization problem that will determine how much labor and capital are needed in order to produce 45,000 tons of steel at minimum cost. Min s.t. L, C20 $ = 45,000 (b) Solve the optimization problem you formulated in part (a). (Hint: When using Excel Solver, start with an initial L> 0 and C> 0. Round your answers to the nearest Integer.) at (L, C) =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![**Steel Production Optimization Problem**
Let \( S \) represent the amount of steel produced (in tons). Steel production is related to the amount of labor used (\( L \)) and the amount of capital used (\( C \)) by the following function:
\[
S = 20L^{0.30}C^{0.70}
\]
In this formula, \( L \) represents the units of labor input and \( C \) the units of capital input. Each unit of labor costs $50, and each unit of capital costs $100.
**(a)** Formulate an optimization problem that will determine how much labor and capital are needed in order to produce 45,000 tons of steel at minimum cost.
Minimize: \[ \text{Cost} = 50L + 100C \]
Subject to: \[ 20L^{0.30}C^{0.70} = 45,000 \]
\[ L, C \geq 0 \]
**(b)** Solve the optimization problem you formulated in part (a). *(Hint: When using Excel Solver, start with an initial \( L > 0 \) and \( C > 0 \). Round your answers to the nearest integer.)*
\[ \$ \boxed{} \] at \((L, C) = (\boxed{}, \boxed{})\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe15c8605-c3c4-4922-bcea-8a06f4b6dc06%2Fac8f3b67-efd5-49a0-9b85-04096cd791ff%2Ff8539y9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Steel Production Optimization Problem**
Let \( S \) represent the amount of steel produced (in tons). Steel production is related to the amount of labor used (\( L \)) and the amount of capital used (\( C \)) by the following function:
\[
S = 20L^{0.30}C^{0.70}
\]
In this formula, \( L \) represents the units of labor input and \( C \) the units of capital input. Each unit of labor costs $50, and each unit of capital costs $100.
**(a)** Formulate an optimization problem that will determine how much labor and capital are needed in order to produce 45,000 tons of steel at minimum cost.
Minimize: \[ \text{Cost} = 50L + 100C \]
Subject to: \[ 20L^{0.30}C^{0.70} = 45,000 \]
\[ L, C \geq 0 \]
**(b)** Solve the optimization problem you formulated in part (a). *(Hint: When using Excel Solver, start with an initial \( L > 0 \) and \( C > 0 \). Round your answers to the nearest integer.)*
\[ \$ \boxed{} \] at \((L, C) = (\boxed{}, \boxed{})\)
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