The demand equation for your company's virtual reality video headsets is 1,500 p = g0.3 where g is the total number of headsets that your company can sell in a week at a price of p dollars. The total manufacturing and shipping cost amounts to $110 per headset. (a) Find the weekly cost, revenue and profit as a function of the demand q for headsets. C(q)= 110g R(q)= 1500g0.7 P(g)= 1500 g0. – 1109 (b) How many headsets should your company sell to maximize profit? (Give your answer to the nearest whole number.) q = 1845 V headsets What is the greatest profit your company can make in a week? (Give your answer to the nearest whole number.) $ E Second derivative test: Your answer above is a critical point for the weekly profit function. To show it is a maximum, calculate the second derivative of the profit function. P"(q)= 86977 Evaluate P"(q) at your critical point. The result is negative , which means that the profit is concave down v at the critical point, and the critical point is a maximum.
The demand equation for your company's virtual reality video headsets is 1,500 p = g0.3 where g is the total number of headsets that your company can sell in a week at a price of p dollars. The total manufacturing and shipping cost amounts to $110 per headset. (a) Find the weekly cost, revenue and profit as a function of the demand q for headsets. C(q)= 110g R(q)= 1500g0.7 P(g)= 1500 g0. – 1109 (b) How many headsets should your company sell to maximize profit? (Give your answer to the nearest whole number.) q = 1845 V headsets What is the greatest profit your company can make in a week? (Give your answer to the nearest whole number.) $ E Second derivative test: Your answer above is a critical point for the weekly profit function. To show it is a maximum, calculate the second derivative of the profit function. P"(q)= 86977 Evaluate P"(q) at your critical point. The result is negative , which means that the profit is concave down v at the critical point, and the critical point is a maximum.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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
Transcribed Image Text:The demand equation for your company's virtual reality video headsets is
1,500
p =
g0.3
where g is the total number of headsets that your company can sell in a week at a price of p dollars. The total manufacturing and shipping cost amounts
to $110 per headset.
(a) Find the weekly cost, revenue and profit as a function of the demand q for headsets.
C(q)= 110g
R(q)= 1500g0.7
P(g)= 1500 g0. – 1109
(b) How many headsets should your company sell to maximize profit? (Give your answer to the nearest whole number.)
q = 1845
V headsets
What is the greatest profit your company can make in a week? (Give your answer to the nearest whole number.)
$ E
Second derivative test:
Your answer above is a critical point for the weekly profit function. To show it is a maximum, calculate the second derivative of the profit function.
P"(q)= 86977
Evaluate P"(qg) at your critical point. The result is negative
, which means that the profit is concave down v
at the critical point, and
the critical point is a maximum.
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