Let r(t) = (-5t³ – 1, t² + 5t³, 3t²). Find the line (L) tangent to (t) at the point (39, -36, 12)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Let r(t) = (-5t³ – 1,t² + 5t³, 3t²).
Find the line (L) tangent to (t) at the point (39, -36, 12)
L: (x, y, z):
=
+t
Transcribed Image Text:Let r(t) = (-5t³ – 1,t² + 5t³, 3t²). Find the line (L) tangent to (t) at the point (39, -36, 12) L: (x, y, z): = +t
Expert Solution
Step 1: We have given a vector-valued function

r(t)=5t31,t2+5t3,3t2

Find the line (L) tangent to r(t) at the point (39,36,12)

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