Find a parabola with equation y = ax2 + bx + c that has slope 8 at x = 1, slope -12 at x = -1, and passes through the point (1, 4). y =

Q: Find the equation of the line perpendicular to y=−2y= through the point (3,2)

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Q: Parallel to y + 8x = 4, through (3, 4); slop- intercept form

A: The line is parallel to y+8x=4, passes through 3, 4

Q: What is the x-coordinate of the x-intercept of the line 2 = 1 when it is graphed in 3 5 with…

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Q: What is the general Cartesian equation of the line that intersects the X axis at the point (9,0) and…

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Q: In the xy-plane, the graph y=x^2+bx+c, where b and c are constants, has x-intercepts at x=-2 and…

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Q: A parabola is given by the equation y = x^2 - 4x + 6. Find k so the line of equation y = 2x - k does…

A: We have to find the value of k for which the line intersect the parabola at two distinct points. To…

Q: slope=2/3; through y-intercept(0,4)   parallel to 2x+4y=9; through (6,1)

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Q: For the equation y= x^2-9/x^2+2 find the intercepts and test for symmetry.

A: First we will find the intercept of the given equation on x-axis that means we will put y=0 in the…

Q: Give 3 points that lie on the parabola y=x^2-5x-2

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Q: Find the equation of the curve whose slope is given by 8 1 + x2 and the curve passes through the…

A: Solution

Q: =a(x-1)^2+2 passes through the points (10,-160) A=

A: NOTE: Refresh your page if you can't see any equations. . the point (10,-160) is on the graph so…