Let R= (2₁1), Find the Point P such that PR has components 82-3,17

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Let \( R = (2, 1) \). Find the point \( P \) such that the vector \(\overrightarrow{PR}\) has components \(\langle -3, 1 \rangle\).

**Solution:**

To find the point \( P = (x, y) \), we need to solve for \( x \) and \( y \) given that the vector \(\overrightarrow{PR} = \langle x - 2, y - 1 \rangle\) has the components \(\langle -3, 1 \rangle\).

1. Set the components equal to each other:

   \[
   x - 2 = -3 \quad \text{and} \quad y - 1 = 1
   \]

2. Solve for \( x \):

   \[
   x - 2 = -3 
   \]
   \[
   x = -3 + 2 
   \]
   \[
   x = -1
   \]

3. Solve for \( y \):

   \[
   y - 1 = 1
   \]
   \[
   y = 1 + 1 
   \]
   \[
   y = 2
   \]

Thus, the point \( P \) is \((-1, 2)\).

**Conclusion:**

The point \( P \) such that vector \(\overrightarrow{PR}\) has components \(\langle -3, 1 \rangle\) when \( R = (2, 1) \) is \( P = (-1, 2) \).
Transcribed Image Text:**Problem Statement:** Let \( R = (2, 1) \). Find the point \( P \) such that the vector \(\overrightarrow{PR}\) has components \(\langle -3, 1 \rangle\). **Solution:** To find the point \( P = (x, y) \), we need to solve for \( x \) and \( y \) given that the vector \(\overrightarrow{PR} = \langle x - 2, y - 1 \rangle\) has the components \(\langle -3, 1 \rangle\). 1. Set the components equal to each other: \[ x - 2 = -3 \quad \text{and} \quad y - 1 = 1 \] 2. Solve for \( x \): \[ x - 2 = -3 \] \[ x = -3 + 2 \] \[ x = -1 \] 3. Solve for \( y \): \[ y - 1 = 1 \] \[ y = 1 + 1 \] \[ y = 2 \] Thus, the point \( P \) is \((-1, 2)\). **Conclusion:** The point \( P \) such that vector \(\overrightarrow{PR}\) has components \(\langle -3, 1 \rangle\) when \( R = (2, 1) \) is \( P = (-1, 2) \).
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