Let n be an integer greater than two. Show that no subgroup of order two is normal in Sn.
Let n be an integer greater than two. Show that no subgroup of order two is normal in Sn.
Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Let n be an integer greater than two. Show that no subgroup of order two is normal in Sn.
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Step 1
To prove that no subgroup of order 2 in the symmetric group Sn (n >2) is normal.
Step 2
Statement of the problem. Note that n>2 ,as for n=2, all subgroups are normal.

Step 3
. We may assume, (after reordering the symbols ) that we are dealing with the subgroup H = {e, (12)}. (any subgroup of order 2 is generated by a transposition)
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