Let lim f(x)=9. Use the limit rules to find the following limit. X-8 lim √f(x) X-8

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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### Limit Calculation Using Limit Rules

Given:
\[ \lim_{x \to 8} f(x) = 9 \]

Use the limit rules to find the following limit:
\[ \lim_{x \to 8} \sqrt{f(x)} \]

### Solution:

Using the limit rule that allows the combination of the limit of a function inside a continuous function, we can proceed as follows:

Given:
\[ \lim_{x \to 8} f(x) = 9 \]

We need to find:
\[ \lim_{x \to 8} \sqrt{f(x)} \]

Since the square root function is continuous, we can write:
\[ \sqrt{\lim_{x \to 8} f(x)} \]

Substituting the known limit:
\[ \sqrt{9} = 3 \]

Therefore:
\[ \lim_{x \to 8} \sqrt{f(x)} = 3 \]

So, the limit is 3.
Transcribed Image Text:### Limit Calculation Using Limit Rules Given: \[ \lim_{x \to 8} f(x) = 9 \] Use the limit rules to find the following limit: \[ \lim_{x \to 8} \sqrt{f(x)} \] ### Solution: Using the limit rule that allows the combination of the limit of a function inside a continuous function, we can proceed as follows: Given: \[ \lim_{x \to 8} f(x) = 9 \] We need to find: \[ \lim_{x \to 8} \sqrt{f(x)} \] Since the square root function is continuous, we can write: \[ \sqrt{\lim_{x \to 8} f(x)} \] Substituting the known limit: \[ \sqrt{9} = 3 \] Therefore: \[ \lim_{x \to 8} \sqrt{f(x)} = 3 \] So, the limit is 3.
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