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Now it's your turn... Be sure to justify each step: use a separate line and cite for each limit law used like the example above. (use a separate piece of paper) Find, if it exists, lim 5x3+4 x-2 X-3

Now it's your turn... Be sure to justify each step: use a separate line and cite for each limit law used like the example above. (use a separate piece of paper) Find, if it exists, lim 5x3+4 x-2 X-3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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lim (x² − 1)¹/³ =(lim(x² − 1))¹/³ x→3 x→3 (lim(x² − 1))¹/³ =(lim(x² + (−1))¹/³ x→3 x→3 (lim(x² + (−1))¹/³=( lim(x²) + lim(−1))¹/³ ((lim(x))² +lim(−1))¹/³ = ((3)² + (−1))¹/³ x→3 By Theorem 2.3 1 v. (Powers and Roots Law) ((3)² + (-1))¹/3= (8)1/3-2 Algebra ( lim(x²) + lim(−1))¹/³ = ( (lim(x))² +lim(-1))¹/³ By 2.3 Theorem 1 v. (Powers and Roots Law) x→3 By 2.3 Theorem 1 i. (Sum law) By 2.2 Theorem 1 Simplification
Transcribed Image Text:lim (x² − 1)¹/³ =(lim(x² − 1))¹/³ x→3 x→3 (lim(x² − 1))¹/³ =(lim(x² + (−1))¹/³ x→3 x→3 (lim(x² + (−1))¹/³=( lim(x²) + lim(−1))¹/³ ((lim(x))² +lim(−1))¹/³ = ((3)² + (−1))¹/³ x→3 By Theorem 2.3 1 v. (Powers and Roots Law) ((3)² + (-1))¹/3= (8)1/3-2 Algebra ( lim(x²) + lim(−1))¹/³ = ( (lim(x))² +lim(-1))¹/³ By 2.3 Theorem 1 v. (Powers and Roots Law) x→3 By 2.3 Theorem 1 i. (Sum law) By 2.2 Theorem 1 Simplification
Now it's your turn... Be sure to justify each step: use a separate line and cite for each limit law used like the example above. (use a separate piece of paper) Find, if it exists, lim 5x3+4 X-2 X-3
Transcribed Image Text:Now it's your turn... Be sure to justify each step: use a separate line and cite for each limit law used like the example above. (use a separate piece of paper) Find, if it exists, lim 5x3+4 X-2 X-3
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