Let < be a partial order on A. Assume that a,b EA are elements with the property that: for any X EA, one has X

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Let < be a partial order on A. Assume that a,b EA are elements with the property that: for any X EA, one has X <a iff X <b. Match the
correct phrase with each blank space in the following proof that a =b.
Proof: By the _(BLANK 1)_ , we have a < a.
Hence by the _(BLANK 2)_ , we have a <b.
Similarly, we have b < a.
Hence by the _(BLANK 3)_, we have a = b.
A. given assumption
BLANK 1
B. reflexive property of <
v BLANK 2
v BLANK 3
C. anti-symmetric property of <
Transcribed Image Text:Let < be a partial order on A. Assume that a,b EA are elements with the property that: for any X EA, one has X <a iff X <b. Match the correct phrase with each blank space in the following proof that a =b. Proof: By the _(BLANK 1)_ , we have a < a. Hence by the _(BLANK 2)_ , we have a <b. Similarly, we have b < a. Hence by the _(BLANK 3)_, we have a = b. A. given assumption BLANK 1 B. reflexive property of < v BLANK 2 v BLANK 3 C. anti-symmetric property of <
Define a relation < on N by X <y iff X =0 and y 0. Match the correct phrase with each blank space in the following proof that < is a strict
order but not a total order.
Proof: Since
(BLANK 1)
the relation < is transitive.
Since_(BLANK 2)__ , the relation < is irreflexive.
Since (BLANK 3)__ , the relation < is asymmetric.
Hence, < is a strict order.
But
(BLANK 4)__, so < is not connected and hence it is not a total order.
there do not exist X,y,Z EN such that X <y and y <z (because
A.
this requires y to be both zero and nonzero)
v BLANK 1
B. we do not have X <y or y <X when X,y #0
BLANK 2
there do not exist X EN such that X <X (because this requires X to
C.
be both zero and nonzero)
v BLANK 3
v BLANK 4
there do not exist X,y EN such that X <y and y <x (because this
D.
requires X to be both zero and nonzero)
Transcribed Image Text:Define a relation < on N by X <y iff X =0 and y 0. Match the correct phrase with each blank space in the following proof that < is a strict order but not a total order. Proof: Since (BLANK 1) the relation < is transitive. Since_(BLANK 2)__ , the relation < is irreflexive. Since (BLANK 3)__ , the relation < is asymmetric. Hence, < is a strict order. But (BLANK 4)__, so < is not connected and hence it is not a total order. there do not exist X,y,Z EN such that X <y and y <z (because A. this requires y to be both zero and nonzero) v BLANK 1 B. we do not have X <y or y <X when X,y #0 BLANK 2 there do not exist X EN such that X <X (because this requires X to C. be both zero and nonzero) v BLANK 3 v BLANK 4 there do not exist X,y EN such that X <y and y <x (because this D. requires X to be both zero and nonzero)
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