Let G3: S -> aSA S -> b A -> bAb A -> aS Use the brute force parsing algorithm to show that there is no left-most derivation for w = abbab. (Show all rounds. Do not use adhoc reasoning) Eliminate derivation from next round only if • prefix of w doesn’t match sentential form • or if |sentential form| > |w| • or if sentential form is all terminals and does not match w

Q: 2. Eliminate all ɛ-productions in the following cfg G: G= ({S,A,B}, {a,b,c}, {S→Aa|BBBA, A bS|ɛ,…

A:

Q: orm pair wise disjointness test for following rules: A→ aB|b|cBB B → aB|bA|aBb C → aaA|b|caB

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A: The hierarchical syntatic structure of the string or language is  called as the Parse tree.

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A: By using the given production we can derive it .As shown in the below

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A: Answer: I have given answered in the handwritten format in brief explanation

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Q: FA - ((А > В) > В)

A: Page 1

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A: Solution:

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Q: When we convert CFG: A-->AYA le, Y-->if le into CNF, the rule one is............ A->AYAle, Y->if | e…

A: Remove start symbol and remove null