Let f(z) = ((z -3i)² + 9)ez-31 The Laurent series representation of f(z) in the domain 0 < |z-3i| <∞o. a) (z − 3i)² + (z − 3i) + Σn=0((n+2)! + i)(z-31)² 1 1 b) 2(z-3i) + En=0; n! (z-31)n c) 9 + 9(z-3i) + Σn=2((n-2)! 2 ((1²2): + 2²/1) (2 − 3i)* O a. O b. O C.
Let f(z) = ((z -3i)² + 9)ez-31 The Laurent series representation of f(z) in the domain 0 < |z-3i| <∞o. a) (z − 3i)² + (z − 3i) + Σn=0((n+2)! + i)(z-31)² 1 1 b) 2(z-3i) + En=0; n! (z-31)n c) 9 + 9(z-3i) + Σn=2((n-2)! 2 ((1²2): + 2²/1) (2 − 3i)* O a. O b. O C.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Exercise 11. *
Let f(z) = ((z – 3i)² + 9)ez-si
The Laurent series representation of f(z) in the domain 0 < ]z – 3i| < o.
a) (z – 3i)2 + (z – 3i) + Ln=0Cn+2)!
1
+
n!) (z-3i)"
1
1
1
b) 2(z – 3i) + En=o;
100
n! (z-3i)n
)(= - 30)"
1
c) 9 + 9(z – 3i) + E=2
а.
O b.
O c.
a.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbc47fdc0-9c50-4344-8904-63924b17ea71%2F58e82859-288a-448c-b079-befb353b3ade%2Ff76i7d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Exercise 11. *
Let f(z) = ((z – 3i)² + 9)ez-si
The Laurent series representation of f(z) in the domain 0 < ]z – 3i| < o.
a) (z – 3i)2 + (z – 3i) + Ln=0Cn+2)!
1
+
n!) (z-3i)"
1
1
1
b) 2(z – 3i) + En=o;
100
n! (z-3i)n
)(= - 30)"
1
c) 9 + 9(z – 3i) + E=2
а.
O b.
O c.
a.
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