Let f(x)-:R->R be defind as (x+4)^2 -5 Find f^-1([4,11]) I understand I am supposed to find the corresponding x values. When you graph the function you see that 4 has the following x values -1 and -7 and 11 has the x values 0 and -8/ So is the pre-image set [-8,7] U [-1.0] ?.

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