Let an isolated system be composed of one part at T1 and second part at T2, with T2>T1. Let the parts be separated by a wall that allows heat flow at only an infinitesimal rate. Show that, when heat dq flows irreversibily from T, to T1, we have entropy change as follow: bp bp ds T1 Hint: Use two heat reservoirs to carry out the change of state reversibly. (which is positive) T2

Let an isolated system be composed of one part at T1 and second part at T2, with T2>T1. Let the parts be separated by a wall that allows heat flow at only an infinitesimal rate. Show that, when heat dq flows irreversibily from T, to T1, we have entropy change as follow: bp bp ds T1 Hint: Use two heat reservoirs to carry out the change of state reversibly. (which is positive) T2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Help
If AH xn--2040 kJ-mol-1 and ASn +103 J-k-1-mol-¹ for the reaction, = C₂Hs (g) +502(g) →3CO₂(g) + 4H₂O(g) Calculate the change in entropy of the surroundings (AS sum) at 298 K (assume constant pressure and temperature). -6.85 J-K-¹-mol-1 +6.85 J-K-¹-mol-1 +103 J-K-1-mol-1 -6850 J-K-¹-mol-1 +6850 J-K-¹-mol-¹
4) The heat capacity of CO2(g) between 30 C and 100 C is given by the following equation Cp = 26.65+ 42.3x10-3 T/K-142.4X10 -7 T 2/K 2 in J K -1 mol -1 . a )Calculate the enthalpy change and b) the entropy change between 30C and 100 C.
Thermodynamic
Help me please...
Only typed solution
Calculate the change in the entropy of a system when going from a condition of 5 accessible microstates to 30 accessible microstates given that the Boltzman constant is 1.38x10 - 23 J/K. Express your result in scientific notation (e.g. the atoms in a mole are 6.022E23).
If the final temperature is 166.66K, determine the change in entropy for each substance.
Calculate the change in molar entropy of graphite when heated from 0.0°C to 27°C. The constant pressure molar heat capacity fits the expression Cp,m /JK¹¹mol-¹ = 16.86 + 4.77 × 10³ K¹T-8.54 × 10-5 K²/T² between 240 K and 330 K.
7. The constant-volume molar heat capacity of a solid may be approximated by 3 12Tª Gy= 5 eD if T << ep. For Al, p = 398 K. What is the entropy change of a 5.0g mass of Al when it is heated at constant volume from 4 K to 176 K?
Calculate ASor for the reaction 3H2(g) +N2(g) → 2NH3(g) at 744 K. Omit terms in the temperature-dependent heat capacities greater than T2/K2. CP,m(H2,g)=22.66+0.0438TK-1.0835x10-4T2K2J-K-1-mol-1 CP,m(N2,g)=30.81-0.01187TK+2.3968x10-5T2K2J-K-1.mol-1 CP,m(NH3,g)=29.29+0.01103TK+4.2446x10-5T2K2J-K-1.mol-1 H2(g) N2(g) NH3(g) So(J.mol-1 K-1) 130.7 191.6 192.8
b) i. Define entropy. ii. 1.0 kg of water at 0 °C is mixed with an equal mass of water at 100 °C. After equilibrium is reached, the mixture has a uniform temperature of 50 °C. Calculate the change in entropy of the water. R= 8.31 kJ mol- K- and for water, Cy = 4186 J kg' K'.