Let A = 0 -2 OC. Three of the five columns in rref(A) have pivots. OD. Two of the five columns in rref(A) have pivots. -3 -2 2 -4 6 0 2 4 b. The dimension of the column space of A is answer): A. rref(A) has a pivot in every row. OB. The basis we found for the column space of A has three vectors. E. rref(A) has a pivot in every column. F. rref(A) is the identity matrix. c. The column space of A is a subspace of d. The geometry of the column space of A is the origin inside R^5 a. A basis for the column space of A is { }. You should be able to explain and justify your answer. Enter a coordinate vector, such as <1,2,3,4> or <1,2,3,4,5>, or a comma separated list of coordinate vectors, such as <1,2,3,4>,<5,6,7,8> or <1,2,3,4,5>,<6,7,8,9,10>. 4 -2 2 1 -2 1 -3 -2 2 because (select all correct answers -- there may be more than one correct because each column vector in A is a vector in R^4 ✓

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Let
A =
0
-2
0
2
-3 -2 2 1
-4
2
-2
1
6
4
-3 -2
4
-2 2
a. A basis for the column space of A is {
}. You should be able to explain and justify your answer. Enter a
coordinate vector, such as <1,2,3,4> or <1,2,3,4,5>, or a comma separated list of coordinate vectors, such as <1,2,3,4>,<5,6,7,8> or
<1,2,3,4,5>,<6,7,8,9,10>.
b. The dimension of the column space of A is
answer):
A. rref(A) has a pivot in every row.
B. The basis we found for the column space of A has three vectors.
OC. Three of the five columns in rref(A) have pivots.
OD. Two of the five columns in rref(A) have pivots.
□ E. rref(A) has a pivot in every column.
□ F. rref(A) is the identity matrix.
c. The column space of A is a subspace of
d. The geometry of the column space of A is the origin inside R^5
because (select all correct answers -- there may be more than one correct
because each column vector in A is a vector in R^4
Transcribed Image Text:Let A = 0 -2 0 2 -3 -2 2 1 -4 2 -2 1 6 4 -3 -2 4 -2 2 a. A basis for the column space of A is { }. You should be able to explain and justify your answer. Enter a coordinate vector, such as <1,2,3,4> or <1,2,3,4,5>, or a comma separated list of coordinate vectors, such as <1,2,3,4>,<5,6,7,8> or <1,2,3,4,5>,<6,7,8,9,10>. b. The dimension of the column space of A is answer): A. rref(A) has a pivot in every row. B. The basis we found for the column space of A has three vectors. OC. Three of the five columns in rref(A) have pivots. OD. Two of the five columns in rref(A) have pivots. □ E. rref(A) has a pivot in every column. □ F. rref(A) is the identity matrix. c. The column space of A is a subspace of d. The geometry of the column space of A is the origin inside R^5 because (select all correct answers -- there may be more than one correct because each column vector in A is a vector in R^4
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