Let 7 and σ be elements of S5 such that: o(1) 2,0 (2) = 1, 0(3) = 4,0 (4) = 5,0 (5) = 3; o(1) = 5,0 (2) = 2, o(3) = 4, 0(4) = 3,0 (5) = 1. Calculate: (a) 100-100 (b) (0-172)33 (c) The order of the cyclic subgroup of S5 generated by 27³. (The order of a group is the number of elements in the group.)
Let 7 and σ be elements of S5 such that: o(1) 2,0 (2) = 1, 0(3) = 4,0 (4) = 5,0 (5) = 3; o(1) = 5,0 (2) = 2, o(3) = 4, 0(4) = 3,0 (5) = 1. Calculate: (a) 100-100 (b) (0-172)33 (c) The order of the cyclic subgroup of S5 generated by 27³. (The order of a group is the number of elements in the group.)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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How do I find the order of the cyclic subgroup of S3 as in c) ?

Transcribed Image Text:Let 7 and σ be elements of S5 such that:
o(1)
2,0 (2) = 1, 0(3) = 4, 0(4) = 5,0 (5) = 3;
o(1) = 5,0 (2) = 2, o(3) = 4, 0(4) = 3,σ(5) = 1.
Calculate:
(a) 100-100
(b) (0-172)33
(c) The order of the cyclic subgroup of S5 generated by o²7³. (The order of a
group is the number of elements in the group.)
"
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