Let /= (-00, 1] and let f(x) =V1-x for x E I. Let G = (-e, e). One of the following open intervals H does not satisfy f(G) = HN1. Select one: a. None of them O b. H=(1- e, 2) OC. H=(1- e, /2)

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Q: 2. Let h(x) = |9 – x²].

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A: Given: x=[-5,-4,-3,-2,-1,0,1,2,3,4,5], A= [0.45    0.61    0.75    0.88    0.96   1    0.96    0.88…

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A: since from graph it clear that  f(x)>0 means f(x) is positive for the   interval  range…

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Q: 28/8<y+9/4<35/8  what is the interval notation

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Q: Let x + 3 x+7 ƒ-¹( - 7) =

A: The given function

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A: We can express the answer using inequality notation as below.

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Linear Algebra

In mathematics, problems can be solved by the arithmetic operators like addition, subtraction, multiplication, and division. In algebra, we represent the numbers by any letter called a variable. If these variables are of degree 1, then it is studied under linear algebra. The first-degree equations involving algebraic expressions are called linear equations. That is, if you represent it by drawing a graph you will get a straight line.