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**Functions and Evaluation** **Given the functions:** \( f(x) = 5x \) \( g(x) = |x - 6| \) \( h(x) = \frac{1}{x + 6} \) **Evaluate the function \((f - g)(x)\) for \( x = 7 \).** \( (f - g)(7) \) is \(\_\_\_\). - The text box contains a placeholder for the answer, and an option for "Undefined." **Explanation** To find \((f - g)(7)\), you need to evaluate both \(f(x)\) and \(g(x)\) at \(x = 7\) and then subtract the results: 1. \( f(7) = 5 \times 7 = 35 \) 2. \( g(7) = |7 - 6| = 1 \) 3. Thus, \((f - g)(7) = 35 - 1 = 34\) Therefore, \((f - g)(7)\) is 34.

**Functions and Evaluation** **Given the functions:** \( f(x) = 5x \) \( g(x) = |x - 6| \) \( h(x) = \frac{1}{x + 6} \) **Evaluate the function \((f - g)(x)\) for \( x = 7 \).** \( (f - g)(7) \) is \(\_\_\_\). - The text box contains a placeholder for the answer, and an option for "Undefined." **Explanation** To find \((f - g)(7)\), you need to evaluate both \(f(x)\) and \(g(x)\) at \(x = 7\) and then subtract the results: 1. \( f(7) = 5 \times 7 = 35 \) 2. \( g(7) = |7 - 6| = 1 \) 3. Thus, \((f - g)(7) = 35 - 1 = 34\) Therefore, \((f - g)(7)\) is 34.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Functions and Evaluation** **Given the functions:** \( f(x) = 5x \) \( g(x) = |x - 6| \) \( h(x) = \frac{1}{x + 6} \) **Evaluate the function \((f - g)(x)\) for \( x = 7 \).** \( (f - g)(7) \) is \(\_\_\_\). - The text box contains a placeholder for the answer, and an option for "Undefined." **Explanation** To find \((f - g)(7)\), you need to evaluate both \(f(x)\) and \(g(x)\) at \(x = 7\) and then subtract the results: 1. \( f(7) = 5 \times 7 = 35 \) 2. \( g(7) = |7 - 6| = 1 \) 3. Thus, \((f - g)(7) = 35 - 1 = 34\) Therefore, \((f - g)(7)\) is 34.
Transcribed Image Text:**Functions and Evaluation** **Given the functions:** \( f(x) = 5x \) \( g(x) = |x - 6| \) \( h(x) = \frac{1}{x + 6} \) **Evaluate the function \((f - g)(x)\) for \( x = 7 \).** \( (f - g)(7) \) is \(\_\_\_\). - The text box contains a placeholder for the answer, and an option for "Undefined." **Explanation** To find \((f - g)(7)\), you need to evaluate both \(f(x)\) and \(g(x)\) at \(x = 7\) and then subtract the results: 1. \( f(7) = 5 \times 7 = 35 \) 2. \( g(7) = |7 - 6| = 1 \) 3. Thus, \((f - g)(7) = 35 - 1 = 34\) Therefore, \((f - g)(7)\) is 34.
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