Let . We say that  is the limit of  f as x->∞ and write limx->∞f(x)=L provided that for each episilon greater than 0 there is a real number N>a such that x>N implies that |f(x)-L|∞f(x)=L and limx->∞g(x)=M, where L, M ∈ ℝ . Prove the following  If  g(x) is not 0 for  x>a and M is not 0 , then limx->∞(f/g)(x)=L/M

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