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Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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<p A horizontal tube-bundle air-cooled exchanger is used to condense steam at 240 F and has the following specifications: Tube Bundle: Steam is flowing inside the tubes tube od 1 in ; tube id 0.834 in ; tube pitch = 2 in (square pitch); k = 26 btu/ft-hr-F There are 12 tube rows with each row containing 72 tubes 20 ft long The tubes are "finned" resulting in a total outside surface area of 3.66 ft2/ft The area of the bare tube exposed (not covered by the fins) is 0.18 ft2/ft The fin height is 0.5 in; The fin thickness is 0.035 in; kfin = 26 btu/ft-hr-F The fin efficiency can be calculated: fineff = 0.0016*x^6 +0.0238*x^5-0.1398*x^4+0.4016*x^3 -0.5391*x^2+0.0004*x + 0.9975 where x = afxf (this is the calculations found in the Unit Op Text Air-side: Air is flowing outside and perpendicular to the tubes at 14 ft/s Air enters the exchanger at 95F and leaves at 205F Air properties at the Air bulk temperature are as follows: Air is at atmosheric pressure viscosity = 0.046 lb/ft-h Cp = 0.25 btu/lb-F k=0.0162 btu/ft-h-F Fa (air flow arrangement factor) can be assummed to be 0.95
Transcribed Image Text:<p A horizontal tube-bundle air-cooled exchanger is used to condense steam at 240 F and has the following specifications: Tube Bundle: Steam is flowing inside the tubes tube od 1 in ; tube id 0.834 in ; tube pitch = 2 in (square pitch); k = 26 btu/ft-hr-F There are 12 tube rows with each row containing 72 tubes 20 ft long The tubes are "finned" resulting in a total outside surface area of 3.66 ft2/ft The area of the bare tube exposed (not covered by the fins) is 0.18 ft2/ft The fin height is 0.5 in; The fin thickness is 0.035 in; kfin = 26 btu/ft-hr-F The fin efficiency can be calculated: fineff = 0.0016*x^6 +0.0238*x^5-0.1398*x^4+0.4016*x^3 -0.5391*x^2+0.0004*x + 0.9975 where x = afxf (this is the calculations found in the Unit Op Text Air-side: Air is flowing outside and perpendicular to the tubes at 14 ft/s Air enters the exchanger at 95F and leaves at 205F Air properties at the Air bulk temperature are as follows: Air is at atmosheric pressure viscosity = 0.046 lb/ft-h Cp = 0.25 btu/lb-F k=0.0162 btu/ft-h-F Fa (air flow arrangement factor) can be assummed to be 0.95
What is the fin perimeter, L, in? What is the fin cross sectional area, S, in2? What is the value for afxf? What is the fin efficiency, nf? What is the overall heat transfer coefficient, Ui, btu/hr-ft2-F?
Transcribed Image Text:What is the fin perimeter, L, in? What is the fin cross sectional area, S, in2? What is the value for afxf? What is the fin efficiency, nf? What is the overall heat transfer coefficient, Ui, btu/hr-ft2-F?
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