A cylindrical specimen of a brass alloy 6.8 mm (0.27 in.) in diameter and 80.1 mm (3.16 in.) long is pulled in tension with a force of 4760 N (1070 Ibf); the force is subsequently released. Compute the final length of the specimen at this time. The tensile stress-strain behavior for this alloy is shown in Animated Figure 7.12. Part 1 What is the applied stress at 4760 N in MPa? i MPa
A cylindrical specimen of a brass alloy 6.8 mm (0.27 in.) in diameter and 80.1 mm (3.16 in.) long is pulled in tension with a force of 4760 N (1070 Ibf); the force is subsequently released. Compute the final length of the specimen at this time. The tensile stress-strain behavior for this alloy is shown in Animated Figure 7.12. Part 1 What is the applied stress at 4760 N in MPa? i MPa
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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3
![Elastic Recovery After Plastic Deformation
A cylindrical specimen of a brass alloy 6.8 mm (0.27 in.) in diameter and 80.1 mm (3.16 in.) long is pulled in tension with a force of
4760 N (1070 Ibf); the force is subsequently released.
Compute the final length of the specimen at this time. The tensile stress-strain behavior for this alloy is shown in Animated Figure
7.12.
Part 1
What is the applied stress at 4760 N in MPa?
O =
MPа](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F69ae72e9-56d1-4942-a117-042e5a25d78f%2F49810fa8-b92f-4523-90bf-afdbec058e63%2Fb8xc5ip_processed.png&w=3840&q=75)
Transcribed Image Text:Elastic Recovery After Plastic Deformation
A cylindrical specimen of a brass alloy 6.8 mm (0.27 in.) in diameter and 80.1 mm (3.16 in.) long is pulled in tension with a force of
4760 N (1070 Ibf); the force is subsequently released.
Compute the final length of the specimen at this time. The tensile stress-strain behavior for this alloy is shown in Animated Figure
7.12.
Part 1
What is the applied stress at 4760 N in MPa?
O =
MPа
![Tensile strength
450 MPa (65,000 psi).
Strain = 0
Stress = 0 MPA
500
Stress = 0 psi
70
Strain = 0
Stress = 0 MPA
60
Stress = 0 psi
400
103 psi
50
MPa
40
Yield strength
250 MPa (36,000 psi)
40
300
200
30
200
30
100
20
10
100
10
to.obs
0.10
0.20
0.30
0.40
Strain
Stress (MPa)
20
Stress (10° psi)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F69ae72e9-56d1-4942-a117-042e5a25d78f%2F49810fa8-b92f-4523-90bf-afdbec058e63%2Fd17xot_processed.png&w=3840&q=75)
Transcribed Image Text:Tensile strength
450 MPa (65,000 psi).
Strain = 0
Stress = 0 MPA
500
Stress = 0 psi
70
Strain = 0
Stress = 0 MPA
60
Stress = 0 psi
400
103 psi
50
MPa
40
Yield strength
250 MPa (36,000 psi)
40
300
200
30
200
30
100
20
10
100
10
to.obs
0.10
0.20
0.30
0.40
Strain
Stress (MPa)
20
Stress (10° psi)
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