LESSON 10 | SESSION 2 Name: Practice Solving Linear Equations in One Variable with the Variable on Both Sides Study the Example showing how to solve a linear equation with the variable on both sides. Then solve problems 1-4. Example The weight of Keiko's kitten is the weight of her puppy. If each animal gains 3 pounds, the kitten will weigh as much as the puppy. The equation w+ 3 = (w + 3) describes this situation, where w is the weight of the puppy now. How much does the puppy weigh now? 6(/w + 3) 이나 + 3) 6w + 3) = 2(w + 3) w + 18 = 2w +6 w-w+ 18 = 2w-w+6 = 6. (w + 3) 18=w+6 12= w The puppy weighs 12 pounds now. 1 In the Example, how much will the kitten weigh if it gains 3 pounds? Show your work.
LESSON 10 | SESSION 2 Name: Practice Solving Linear Equations in One Variable with the Variable on Both Sides Study the Example showing how to solve a linear equation with the variable on both sides. Then solve problems 1-4. Example The weight of Keiko's kitten is the weight of her puppy. If each animal gains 3 pounds, the kitten will weigh as much as the puppy. The equation w+ 3 = (w + 3) describes this situation, where w is the weight of the puppy now. How much does the puppy weigh now? 6(/w + 3) 이나 + 3) 6w + 3) = 2(w + 3) w + 18 = 2w +6 w-w+ 18 = 2w-w+6 = 6. (w + 3) 18=w+6 12= w The puppy weighs 12 pounds now. 1 In the Example, how much will the kitten weigh if it gains 3 pounds? Show your work.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![**Lesson 10 | Session 2**
**Practice Solving Linear Equations in One Variable with the Variable on Both Sides**
*Study the Example showing how to solve a linear equation with the variable on both sides. Then solve problems 1–4.*
---
**Example**
The weight of Keiko’s kitten is \(\frac{1}{6}\) the weight of her puppy. If each animal gains 3 pounds, the kitten will weigh \(\frac{1}{3}\) as much as the puppy. The equation \(\frac{1}{6}w + 3 = \frac{1}{3}(w + 3)\) describes this situation, where \(w\) is the weight of the puppy now. How much does the puppy weigh now?
\[
6\left(\frac{1}{6}w + 3\right) = 6 \cdot \frac{1}{3}(w + 3)
\]
\[
6\left(\frac{1}{6}w + 3\right) = 2(w + 3)
\]
\[
w + 18 = 2w + 6
\]
\[
w - w + 18 = 2w - w + 6
\]
\[
18 = w + 6
\]
\[
12 = w \quad \text{The puppy weighs 12 pounds now.}
\]
---
1. **In the Example, how much will the kitten weigh if it gains 3 pounds? Show your work.**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F851fec11-8f5e-46f3-a914-a2343bbfef9e%2F85b2e542-818b-4552-953b-7bf44268b5f8%2Frunp1f9_processed.png&w=3840&q=75)
Transcribed Image Text:**Lesson 10 | Session 2**
**Practice Solving Linear Equations in One Variable with the Variable on Both Sides**
*Study the Example showing how to solve a linear equation with the variable on both sides. Then solve problems 1–4.*
---
**Example**
The weight of Keiko’s kitten is \(\frac{1}{6}\) the weight of her puppy. If each animal gains 3 pounds, the kitten will weigh \(\frac{1}{3}\) as much as the puppy. The equation \(\frac{1}{6}w + 3 = \frac{1}{3}(w + 3)\) describes this situation, where \(w\) is the weight of the puppy now. How much does the puppy weigh now?
\[
6\left(\frac{1}{6}w + 3\right) = 6 \cdot \frac{1}{3}(w + 3)
\]
\[
6\left(\frac{1}{6}w + 3\right) = 2(w + 3)
\]
\[
w + 18 = 2w + 6
\]
\[
w - w + 18 = 2w - w + 6
\]
\[
18 = w + 6
\]
\[
12 = w \quad \text{The puppy weighs 12 pounds now.}
\]
---
1. **In the Example, how much will the kitten weigh if it gains 3 pounds? Show your work.**
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